Java Array.asList错误

我已经用asList创建了一个数组列表，但是我得到了很多错误

@Service
public class ArticleService {

List<Article> articleList = new ArrayList<Article>(Arrays.asList(
new Article( id:"1", name: "Article 01", description: "Description 01" ),
new Article( id:"2", name: "Article 02", description: "Description 02" ),
new Article( id:"3", name: "Article 03", description: "Description 03" )
));

public List<Article> getAllArticles(){
return articleList;
}
}

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使用Arrays.asList的正确方法：

List<Article> articleList = Arrays.asList(new Article(),new Article(),new Article());

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假设你的文章分类如下，如果不是，请做适当的分类

class Article{
       String id;
       String article;
       String description;
   Article(String id ,String articleName,String description)
   {
      this.id=id;
      this.articleName = articleName;
      this.description = description;
   }
   ........
   //your getter/setters are defined here.

}

现在你应该在你的主课堂上使用它们，如下所示

List<Article> articleList = new ArrayList<Article>(Arrays.asList(
                new Article( "1","Article 01", "Description 01" ),
                new Article( "2","Article 02","Description 02" ),
                new Article("3","Article 03","Description 03" )
                ));

 //this is the correct way of using it.

---

很多错误意味着什么样的错误？请发布任何编译器错误，并写一个最小和完整的例子。是的。。。那不是Java。新物品id:1，名称：物品01，描述：描述01？？？也许从学习语言的基本语法开始吧。我正试图上传一张图片，但应用程序像预期的那样崩溃了类型的预期Java非法开始

List<Article> articleList = new ArrayList<Article>(Arrays.asList(
                new Article( "1","Article 01", "Description 01" ),
                new Article( "2","Article 02","Description 02" ),
                new Article("3","Article 03","Description 03" )
                ));

 //this is the correct way of using it.

// you can execute your business logic like below code

List<Article> articleList=null;
        articleList = (List<Article>) new ArrayList();

        Article art = new Article();
        art.setId(0);
        art.setName("Article 01");
        art.setDescription("Description 01");
        articleList.add(art);