Java 如何在数据库中插入数据后按顺序更改textview

我的要求是,

我有预告片1号和电影的名字。现在，一旦我在表中插入了数据，我需要将文本更改为拖车编号2，直到拖车编号5。因为只需要插入5个数据。此外，我将检查表中是否已经存在1号拖车。如果不存在，则在表中插入，但如果存在，则将文本更改为拖车编号2。这正是它应该起作用的场景

但在我的例子中，当我插入1号拖车时，它跳到5号拖车，而不是不显示2号拖车

点击按钮后

boolean isFirstTrailerNumberExist = myDb.isExist("Trailer Number 1");
            boolean isSecondTrailerNumberExist = myDb.isExist("Trailer Number 2");
            boolean isThirdTrailerNumberExist = myDb.isExist("Trailer Number 3");
            boolean isFourthTrailerNumberExist = myDb.isExist("Trailer Number 4");
            boolean isFifthTrailerNumberExist = myDb.isExist("Trailer Number 5");

 if(isFirstTrailerNumberExist) {
                Toast.makeText(this, "Trailer Number 1 already Exist", Toast.LENGTH_SHORT)
                        .show();

            } else {
                boolean isInserted = myDb.insertData(trailerNumberName.getText().toString(),
                        trailerNumberCount.getText().toString());
                if(isInserted){

                    Toast.makeText(TrailerNumberActivity.this,"Inserted successfully",Toast.LENGTH_SHORT)
                            .show();
                    trailerNumberName.setText("Trailer Number 2");
                }
                else{
                    Toast.makeText(TrailerNumberActivity.this,"Insertion failed",Toast.LENGTH_SHORT)
                            .show();
                }
            }

if(isSecondTrailerNumberExist){
                Toast.makeText(this,"Trailer Number 2 already Exist",Toast.LENGTH_SHORT)
                        .show();
            }
            else {
                boolean isInserted = myDb.insertData(trailerNumberName.getText().toString(),
                        trailerNumberCount.getText().toString());
                if(isInserted){

                    Toast.makeText(TrailerNumberActivity.this,"Inserted successfully",Toast.LENGTH_SHORT)
                            .show();
                    trailerNumberName.setText("Trailer Number 3");
                }
                else{
                    Toast.makeText(TrailerNumberActivity.this,"Insertion failed",Toast.LENGTH_SHORT)
                            .show();
                }
            }
//the same repeats for third, fourth and fifth trailer too to check in db

if(isThirdTrailerNumberExist){
                Toast.makeText(this,"Trailer Number 3 already Exist",Toast.LENGTH_SHORT)
                        .show();
            }
            else {
                boolean isInserted = myDb.insertData(trailerNumberName.getText().toString(),
                        trailerNumberCount.getText().toString());
                if(isInserted){

                    Toast.makeText(TrailerNumberActivity.this,"Inserted successfully",Toast.LENGTH_SHORT)
                            .show();
                    trailerNumberName.setText("Trailer Number 4");
                }
                else{
                    Toast.makeText(TrailerNumberActivity.this,"Insertion failed",Toast.LENGTH_SHORT)
                            .show();
                }
            }

            if(isFourthTrailerNumberExist){
                Toast.makeText(this,"Trailer Number 4 already Exist",Toast.LENGTH_SHORT)
                        .show();
            }
            else {
                boolean isInserted = myDb.insertData(trailerNumberName.getText().toString(),
                        trailerNumberCount.getText().toString());
                if(isInserted){

                    Toast.makeText(TrailerNumberActivity.this,"Inserted successfully",Toast.LENGTH_SHORT)
                            .show();
                    trailerNumberName.setText("Trailer Number 5");
                }
                else{
                    Toast.makeText(TrailerNumberActivity.this,"Insertion failed",Toast.LENGTH_SHORT)
                            .show();
                }
            }

            if(isFifthTrailerNumberExist){
                Toast.makeText(this,"Trailer Number 5 already Exist",Toast.LENGTH_SHORT)
                        .show();
            }
            else {
                boolean isInserted = myDb.insertData(trailerNumberName.getText().toString(),
                        trailerNumberCount.getText().toString());
                if(isInserted){

                    Toast.makeText(TrailerNumberActivity.this,"Inserted successfully",Toast.LENGTH_SHORT)
                            .show();
                    trailerNumberName.setText("Trailer Number 1");
                }
                else{
                    Toast.makeText(TrailerNumberActivity.this,"Insertion failed",Toast.LENGTH_SHORT)
                            .show();
                }
            }

---

这就是我重复显示到拖车5的方式，但问题是在插入拖车1后，它会跳到拖车5。

当然，它会跳到拖车5，因为当您最初单击按钮时，all---TrailerNumberExist将返回false，因此它会依次将文本设置为“拖车2号”，“3号拖车”等，直到停在“5号拖车”处

像这样做

 if(!isFirstTrailerNumberExist) {
    // insert and show your entry here
    insertDataAndUpdateText("Trailer Number 2");
}else if(!isSecondTrailerNumberExist){
    // insert and show your entry here
    insertDataAndUpdateText("Trailer Number 3");
}else if(!isThirdTrailerNumberExist){
    // insert and show your entry here
    insertDataAndUpdateText("Trailer Number 4");
} 

等等。。 使用单一方法使您的代码最优化

---

现在，单击按钮将按顺序输入，并显示输出

谢谢。因此，我需要检查else if（！）“而不是if，对吗？正确。使用调试器，它将准确地告诉您发生了什么。您可以在这里学习