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Javascript 无法在单击事件时获取li的id_Javascript_Jquery - Fatal编程技术网

Javascript 无法在单击事件时获取li的id

Javascript 无法在单击事件时获取li的id,javascript,jquery,Javascript,Jquery,我有这个代码来显示选项卡 $start = strtotime($_GET['date']); $dates = array(); for ($i = 0; $i <= 7; $i++) { $date = date('Y-m-d', strtotime("+$i day", $start)); $date1 = $date; $day = date('D', strtotime($date1)); $date = explode('-',

我有这个代码来显示选项卡

  $start = strtotime($_GET['date']);
   $dates = array();
   for ($i = 0; $i <= 7; $i++) {

    $date = date('Y-m-d', strtotime("+$i day", $start));
    $date1 = $date;
    $day = date('D', strtotime($date1));
    $date = explode('-', $date);
    $dateinput = date('Y-m-d', strtotime("+$i day", $start));
    $date = $date[2];
    echo '<li class="lia" id="'.$dateinput.'"><input type="hidden"    class="getdate" value="'.$dateinput.'"><a href="#tabs-'.$i.'" class="date">' .    $date . '  ' . $day . '</a></li>';

    }
$start=strottime($\u GET['date']);
$dates=array();
对于($i=0;$i替换

var libtn= $("li.lia").find("li").attr("id");

检查一下

在同一个元素中找不到元素本身

编辑

我希望你在每一个li上都有
lia
课程

那么, 这是密码

$("li.lia").each(function(i,j){
 console.log($(this).attr("id")); // use as per your requirement
});

将var libtn=$(“li.lia”).find(“li”).attr(“id”)行替换为var libtn=$(“li.lia”).attr(“id”);您正在使用哪个日期选择器?jquery DatePickerHanks,但这只是给我第一个。我需要所有li的id。让我编辑一下我的问题。欢迎!如果它解决了您的问题,请接受我的答案。
var libtn = $("li.lia").attr("id");
$("li.lia").each(function(i,j){
 console.log($(this).attr("id")); // use as per your requirement
});