Javascript 有没有办法重新定义“a”；让我们；当某个条件变为真时的值？

温柔一点：

我是Javascript新手，对如何在循环中的条件变为真后重新定义“let”值的for循环（或建议更合适的另一个循环）感到好奇。当最后一个“else if”条件变为True时，它将通过向其添加常量来重新定义

Value1

值，然后再次开始前两个条件检查。无限循环

我在下面提供了我当前代码的一个示例：

const fetch = require('node-fetch');
const api_url = 'https://an-api-i-am-using-that-returns-Value1.com'
let Value1 = 100;
const add_to = 10;

async function getTotal() {

    const response = await fetch(api_url);

    Number_Returned = await response.json();
    Number_Left = Value1 - Number_Returned
    Time_Left = Number_Left * 60;

    if (Number_Left > 0){
        console.log(Number_Left)

        var d = parseInt(Time_Left / (3600 * 24));
        console.log(d)

        nd = Time_Left % (24 * 3600);
        var h = parseInt(nd/3600);
        console.log(h)

        Time_Left %= 3600;
        var m = parseInt((Time_Left/60));
        console.log(m)

        const longEnUSFormatter = new Intl.DateTimeFormat('en-US', { dateStyle: 'full', timeStyle: 'long' });

        var date = new Date();
        date.setMinutes(date.getMinutes() + (d * 24 * 60) + (h * 60) + m);
        console.log(longEnUSFormatter.format(date))
    }
    else if (Number_Left == 0 && Value1 == Number_Returned) {
        console.log(Number_Left)

        d = "no";
        console.log(d)
        h = "no";
        console.log(h)
        m = "no";
        console.log(m)
        date = "Today";
        console.log(date)
    }
    else if (Number_Left < 0) {
        console.log(Number_Left)

        d = "didn't work";
        console.log(d)
        h = "didn't work";
        console.log(h)
        m = "didn't work";
        console.log(m)
        date = "didn't work";
        console.log(date)
        Value1 =+ add_to;
    }
}

async function begin(){
    console.log('calling');
    const result = await getTotal();
    console.log(Value1);
}

begin();

当（Number\u Left==0&&Value1==Number\u Returned）为True时：

当（数字_左<0）为真时：

重申一下，一旦最后一个条件变为真，我想将常量添加到let值

Value1

，再次开始

（Number\u Left>0）

和

（Number\u Left==0&&Value1==Number\u Returned）

条件检查

---

让我知道我是否可以更具体地说明我正在努力实现的目标。提前感谢。

当您要添加值并设置它时，语法是

+=

而不是

=+

，如果您更改以下内容，您可能会得到所需的结果：

Value1 =+ add_to;

（请注意）：

---

为了完成我需要的代码，我必须重写它。这可能不是最好的编码，但它适用于我试图实现的目标：

const api_url = 'https://an-api-i-am-using-that-returns-Value1.com';

    async function getTotal(){
        resp = await fetch(api_url);
        Number_Returned = await resp.text();
        return Number_Returned
    }

    async function checkValue1(){
        Value1 = 100;
        const add_to = 10;
        cur = await getTotal();

        if (Value1>=cur){
            return cur
        }
        else if (Value1<cur){
            Value1 = Value1 + add_to
            return cur
        }
    }

    async function calculateTotal(){
        const theValue1 = await checkValue1();
        const numDifference = 2880;
        let numLeft = (Value1 - numDifference) - theValue1;
        let timeDelta = numLeft * 60.097;
        return timeDelta
    }

    async function calcDate(){
        let timeLeft = await calculateTotal();
        let d = parseInt(timeLeft / (3600 * 24));
        document.getElementById('days').innerHTML = d;
        nd = timeLeft % (24 * 3600);
        let h = parseInt(nd/3600);
        document.getElementById('hours').innerHTML = h;
        timeLeft %= 3600;
        let m = parseInt((timeLeft/60));
        document.getElementById('mins').innerHTML = m;
        const longEnUSFormatter = new Intl.DateTimeFormat('en-US', { dateStyle: 'full', timeStyle: 'long' });
        let date = new Date();
        date.setMinutes(date.getMinutes() + (d * 24 * 60) + (h * 60) + m);
        document.getElementById('date').innerHTML = longEnUSFormatter.format(date);
}

calcDate();

const-api\u-url=”https://an-api-i-am-using-that-returns-Value1.com';
异步函数getTotal（）{
resp=等待获取（api_url）；
返回的数字=等待响应文本（）；
返回号码
}
异步函数checkValue1（）{
值1=100；
const add_to=10；
cur=等待getTotal（）；
如果（值1>=cur）{
返回电流
}
else if（Value1感谢您的评论，这确实解决了将
add_添加到
Value1
的问题，但我希望“if”语句重新启动并再次开始检查前两个条件。现在它只是停留在最后一个“else if”上条件。感谢您的评论，这确实解决了将
add_添加到
Value1
的问题，但我希望“if”语句重新启动并开始检查前两个条件。现在它只是停留在最后一个“else if”上条件。更改值后可以再次调用该函数吗？在正常的for/while循环中，您将使用
continue
，但您处于for循环中。谢谢您的建议。我现在要尝试一下。
calling
-7
didn't work
didn't work
didn't work
didn't work
10

Value1 =+ add_to;

Value1 += add_to;

const api_url = 'https://an-api-i-am-using-that-returns-Value1.com';

    async function getTotal(){
        resp = await fetch(api_url);
        Number_Returned = await resp.text();
        return Number_Returned
    }

    async function checkValue1(){
        Value1 = 100;
        const add_to = 10;
        cur = await getTotal();

        if (Value1>=cur){
            return cur
        }
        else if (Value1<cur){
            Value1 = Value1 + add_to
            return cur
        }
    }

    async function calculateTotal(){
        const theValue1 = await checkValue1();
        const numDifference = 2880;
        let numLeft = (Value1 - numDifference) - theValue1;
        let timeDelta = numLeft * 60.097;
        return timeDelta
    }

    async function calcDate(){
        let timeLeft = await calculateTotal();
        let d = parseInt(timeLeft / (3600 * 24));
        document.getElementById('days').innerHTML = d;
        nd = timeLeft % (24 * 3600);
        let h = parseInt(nd/3600);
        document.getElementById('hours').innerHTML = h;
        timeLeft %= 3600;
        let m = parseInt((timeLeft/60));
        document.getElementById('mins').innerHTML = m;
        const longEnUSFormatter = new Intl.DateTimeFormat('en-US', { dateStyle: 'full', timeStyle: 'long' });
        let date = new Date();
        date.setMinutes(date.getMinutes() + (d * 24 * 60) + (h * 60) + m);
        document.getElementById('date').innerHTML = longEnUSFormatter.format(date);
}

calcDate();