Javascript 将嵌套数组映射到父对象';s键值对
我有一个对象数组,看起来像:Javascript 将嵌套数组映射到父对象';s键值对,javascript,arrays,Javascript,Arrays,我有一个对象数组,看起来像: { name: 'steve', plaintiff:'IRS' amount: 5000, otherliens:[ { amount:5000, plaintiff:'irs' }, {amount:5000, plaintiff:'irs' } ] } 我需要将其作为csv发送,因此我需要
{
name: 'steve',
plaintiff:'IRS'
amount: 5000,
otherliens:[
{
amount:5000,
plaintiff:'irs'
},
{amount:5000,
plaintiff:'irs'
}
]
}
我需要将其作为csv发送,因此我需要映射并迭代此子阵列,并将其展平到对象中,如下所示:
{
name:'steve',
plaintiff:'irs',
amount:5000,
plaintiff2:'irs',
amount2:5000,
plaintiff3:'irs',
amount3:5000
}
我通常用于执行此过程的代码是通过使用arr.map(a,i=>{a[i]?a[i].amount=a[i].amount})将原始数组的内容映射到一个新数组中
我能够通过简单地猜测大量条目(请参见电话和电子邮件)来处理基于字符串的子数组,因为如果我返回null,它只会返回空白,在csv中,这并不是最糟糕的事情。但我不能这样做,因为访问不存在的元素的子属性显然是行不通的。这是im使用的映射,其中emailAddresses是一个字符串数组,PhoneNumber是一个字符串数组,Otherlien是一个对象数组
任何帮助都将被感激并牢记在心,因为大容量数据传输和CSV最终将有固定数量的列,我不介意空值,所以我猜您将采用最长的子数组长度,并在所有其他对象中使用它
完整代码
prospects.map((list, i) => {
result[i]
? (result[i].fullName = list.fullName)
(result[i].First_Name = list.firstName)
(result[i].Last_Name = list.lastName)
(result[i].Delivery_Address = list.deliveryAddress)
(result[i].City = list.city)
(result[i].State = list.state)
(result[i].Zip_4 = list.zip4)
(result[i].County = list.county)
(result[i].plaintiff= list.plaintiff)
(result[i].Amount = list.amount)
(result[i].age = list.age)
(result[i].dob= list.dob)
(result[i].snn= list.ssn)
(result[i].plaintiff2= list.otherliens[1].plaintiff )
(result[i].filingDate2= list.otherliens[1].filingDate)
(result[i].amount2= list.otherliens[1].amount )
(result[i].plaintiff3= list.otherliens[2].plaintiff)
(result[i].filingDate3= list.otherliens[2].filingDate )
(result[i].amount3= list.otherliens[2].amount )
(result[i].amount4= list.otherliens[3].amount)
(result[i].plaintiff4= list.otherliens[3].plaintiff )
(result[i].filingDate4= list.otherliens[3].filingDate )
(result[i].phone1 = list.phones[0])
(result[i].phone2 = list.phones[1])
(result[i].phone3 = list.phones[2])
(result[i].phone4 = list.phones[3])
(result[i].phone5 = list.phones[4])
(result[i].phone6 = list.phones[5])
(result[i].phone7 = list.phones[6])
(result[i].phone8 = list.phones[7])
(result[i].phone9 = list.phones[8])
(result[i].emailAddress1 = list.emailAddresses[0])
(result[i].emailAddress2 = list.emailAddresses[1])
(result[i].emailAddress3 = list.emailAddresses[2])
(result[i].emailAddress4 = list.emailAddresses[3])
(result[i].emailAddress5 = list.emailAddresses[4])
(result[i].emailAddress6 = list.emailAddresses[5])
(result[i].emailAddress7 = list.emailAddresses[6])
: (result[i] = {
Full_Name: list.fullName ,
First_Name: list.firstName,
Last_Name: list.lastName,
Delivery_Address: list.deliveryAddress,
City: list.city,
State: list.state,
Zip_4: list.zip4,
County: list.county,
dob: list.dob,
ssn:list.ssn,
age:list.age,
Amount: list.amount,
plaintiff: list.plaintiff,
filingDate: list.filingDate,
phone1:list.phones[0],
phone2:list.phones[1],
phone3:list.phones[3],
phone4:list.phones[4],
phone5:list.phones[5],
phone6:list.phones[6],
phone7:list.phones[7],
phone8:list.phones[8],
emailAddress1:list.emailAddresses[0],
emailAddress2:list.emailAddresses[1],
emailAddress3:list.emailAddresses[2],
emailAddress4:list.emailAddresses[3],
emailAddress5:list.emailAddresses[4],
emailAddress6:list.emailAddresses[5],
plaintiff2: list.otherliens[1].plaintiff,
amount2: list.otherliens[1].amount,
filingDate2: list.otherliens[1].filingDate,
plaintiff3: list.otherliens[2].plaintiff,
filingDate3: list.otherliens[2].filingDate,
amount3: list.otherliens[2].amount,
plaintiff4: list.otherliens[3].plaintiff,
amount4: list.otherliens[3].amount,
filingDate4: list.otherliens[3].filingDate,
})
} );
使用循环从嵌套数组中指定属性,而不是对项数进行硬编码 我也不认为有必要使用条件表达式。由于每个输入元素直接映射到输出元素,因此不会有需要更新的
result[i]
result=prospects.map({fullName,firstName,lastName,deliveryAddress,city,state,zip4,country,原告,金额,年龄,dob,ssn,其他客户,电话,emailaddress})=>{
设obj={
全名:全名,
名字:名字,
姓氏:姓氏,
送货地址:送货地址,
城市:城市,,
州:州,,
Zip_4:zip4,
县:县,,
原告:原告,,
金额:金额,,
年龄:年龄,,
多布:多布,
ssn:ssn
};
其他留置权。forEach({原告,金额},i)=>{
obj[`原告${i+2}`]=原告;
obj[`amount${i+1}`]=金额;
});
phones.forEach((phone,i)=>obj[`phone${i+1}`]=phone);
forEach((addr,i)=>obj[`emailAddress${i+1}`]=addr);
返回obj;
})
如果未使用返回值,则应使用forEach
,而不是map
。