Javascript 如何重新编写batch.delete函数以用于实时数据库？

我有一个谷歌云功能，目前为firestore工作。我能够将第一个变量转换为实时数据库，但我不太了解（）如何将其转换为其他变量

如何在实时数据库中执行此操作？

  exports.cleanupUser = functions.auth.user().onDelete(async (user) => {
   const dbRef = admin.database().ref('stripe_customers');//admin.firestore().collection('stripe_customers');
   const customer = (await dbRef.doc(user.uid).get()).data();
   await stripe.customers.del(customer.customer_id);
   // Delete the customers payments & payment methods in firestore.
   const batch = admin.firestore().batch();
   const paymetsMethodsSnapshot = await dbRef
     .doc(user.uid)
     .collection('payment_methods')
     .get();
   paymetsMethodsSnapshot.forEach((snap) => batch.delete(snap.ref));
   const paymentsSnapshot = await dbRef
     .doc(user.uid)
     .collection('payments')
     .get();
   paymentsSnapshot.forEach((snap) => batch.delete(snap.ref));
 
   await batch.commit();
 
   await dbRef.doc(user.uid).delete();
   return;
 });

我尝试了以下操作，但似乎不起作用：

 exports.cleanupUser = functions.auth.user().onDelete(async (user) => {
   const dbRef = admin.database().ref('stripe_customers');//admin.firestore().collection('stripe_customers');
   const customer = (await dbRef.child(user.uid).get()).data();
   await stripe.customers.del(customer.customer_id);
   // Delete the customers payments & payment methods in firestore.
   const batch = admin.database().batch();
   const paymetsMethodsSnapshot = await dbRef
    .child(user.uid).child('payment_methods').get();
   paymetsMethodsSnapshot.forEach((snap) => batch.delete(snap.ref));
   const paymentsSnapshot = await dbRef
    .child(user.uid).child('payments').get();
   paymentsSnapshot.forEach((snap) => batch.delete(snap.ref));
 
   await batch.commit();
 
   await dbRef.child(user.uid).delete();
   return;
 });

---

实时数据库的数据结构比Firestore简单得多，Firestore既有优点也有缺点

对于实时数据库，如果删除某个位置的数据，则该位置下的所有数据都将被删除。这与Firestore不同，Firestore需要删除要删除的文档的每个子集合中的每个文档

简而言之，这个firestore代码

const dbRef = admin.firestore().collection('stripe_customers');
const batch = admin.firestore().batch();
const paymetsMethodsSnapshot = await dbRef
  .doc(user.uid)
  .collection('payment_methods')
  .get();
paymetsMethodsSnapshot.forEach((snap) => batch.delete(snap.ref));
const paymentsSnapshot = await dbRef
  .doc(user.uid)
  .collection('payments')
  .get();
paymentsSnapshot.forEach((snap) => batch.delete(snap.ref));

await batch.commit();

await dbRef.doc(user.uid).delete();

变平到刚好

const dbRef = admin.database().ref('stripe_customers');
await dbRef.child(user.uid).remove();

这使您的功能：

exports.cleanupUser = functions.auth.user()
  .onDelete(async (user) => {
    const dbRef = admin.database().ref('stripe_customers');

    // Firestore's .get() is the same as RTDB's .once('value')
    // Firestore's .data() is the same as RTDB's .val()
    const customer = (await dbRef.child(user.uid).once('value')).val();

    // user data already deleted? do nothing rather than throw errors.
    if (customer === null) {
      return;
    }

    await stripe.customers.del(customer.customer_id);

    await dbRef.child(user.uid).remove();
  });

---

Firestore对实时数据库的批写操作的等效功能是多路径更新，您可以将要写入的路径和值传递给

update（）

函数。如果指定

null

作为路径的值，则该路径将被删除。转换整个函数超出了堆栈溢出的范围，但这应该是一个很好的起点。