Javascript 如何仅在发送消息后发送消息。删除（）超时

我想发送

message.channel.send（'send me after timeout'）仅在消息之后。删除（）超时

可以这样做：

message.channel.send（嵌入）
。然后（message=>message.delete（{timeout:4000}）。然后（m=>m.channel.send（“超时后发送我”））。catch（O_O=>{}）；

const Discord = require('discord.js');

module.exports = {
    name: 'coin',
    description: 'Toss Coin!',
    aliases: 'toss',
    execute(message, args) {
        message.delete().catch(O_o => {});

        const embed = new Discord.MessageEmbed()

        .setTitle(`${message.author.username}`)
        .setColor('#6d00c1')
        .setImage('https://i.pinimg.com/originals/8f/06/04/8f0604aedc34d33d2f41113c312a588d.gif');
        
        message.channel.send(embed)
        .then(message => { message.delete({ timeout: 4000 })}).catch(O_o => {});

        message.channel.send('Send me after timeout');
    },
};