如果存在任何匹配，则两个数组（一个嵌套数组和一个平面数组）上的JavaScript部分匹配应返回true

我需要通过给定数组“results”的每个节点进行部分匹配。匹配需要解析原始输入字段中由空格分隔的每个字符串。以下是我基本需要的样本请不要使用插件

我有两组数组：结果列表数组和输入字段数组，假设：

如果输入搜索词：“ABC pa 2014”-我现在将其存储在一个数组中，以便使用indexOf。但是，它匹配每个空格分隔项的完整字符串

结果列表数组：

[
  {
    "sIndex": 0,
    "sItem": {
      "cName": "ABC Partners",
      "cId": 0
    }
  },
  {
    "sIndex": 1,
    "sItem": {
      "cName": "ABC Partners",
      "cId": 0,
      "pName": "[ABC] ABC Description",
      "pTick": "ABC",
      "pId": 0,
      "dName": "[2014] ABC Db",
      "dYear": [
        "2014"
      ],
      "dId": 0
    }
  },
  {
    "sIndex": 2,
    "sItem": {
      "cName": "ABC Partners",
      "cId": 0,
      "pName": "[ABC] ABC Description Two",
      "pTick": "ABC",
      "pId": 0,
      "dName": "[2014] ABC Db",
      "dYear": [
        "2014"
      ],
      "dId": 0
    }
  },

用于测试目的的完整阵列：

[{"sIndex":0,"sItem":{"cName":"ABC Partners","cId":0}},{"sIndex":1,"sItem":{"cName":"ABC Partners","cId":0,"pName":"[ABC] ABC Partners","pTick":"ABC","pId":0}},{"sIndex":2,"sItem":{"cName":"ABC Partners","cId":0,"pName":"[ABC] ABC Partners","pTick":"ABC","pId":0,"dName":"[2009] ABC Partners DB","dYear":"2009","dId":0}},{"sIndex":3,"sItem":{"cName":"ABC Partners","cId":0,"pName":"[ABC] ABC Partners","pTick":"ABC","pId":0,"dName":"[2009] Scenario 1 DB","dYear":"2009","dId":1}},{"sIndex":4,"sItem":{"cName":"ABC Partners","cId":0,"pName":"[ABC] ABC Partners","pTick":"ABC","pId":0,"dName":"[2009] Scenario 1 ExpResults DB","dYear":"2009","dId":2}},{"sIndex":5,"sItem":{"cName":"ABC Partners","cId":0,"pName":"[ABC] ABC Partners","pTick":"ABC","pId":0,"dName":"[2009] Scenario 2 DB","dYear":"2009","dId":3}},{"sIndex":6,"sItem":{"cName":"ABC Partners","cId":0,"pName":"[ABC] ABC Partners","pTick":"ABC","pId":0,"dName":"[2009] Scenario 2 ExpResults DB","dYear":"2009","dId":4}},{"sIndex":7,"sItem":{"cName":"ABC Partners","cId":0,"pName":"[ABC] ABC Partners","pTick":"ABC","pId":0,"dName":"[2009] Scenario 3 BaseDB","dYear":"2009","dId":5}},{"sIndex":8,"sItem":{"cName":"ABC Partners","cId":0,"pName":"[ABC] ABC Partners","pTick":"ABC","pId":0,"dName":"[2009] Scenario 3 DB","dYear":"2009","dId":6}},{"sIndex":9,"sItem":{"cName":"ABC Partners","cId":0,"pName":"[ABC] ABC Partners","pTick":"ABC","pId":0,"dName":"[2009] Scenario 3 ExpResults DB","dYear":"2009","dId":7}},{"sIndex":10,"sItem":{"cName":"ABC Partners","cId":0,"pName":"[ABC] ABC Partners","pTick":"ABC","pId":0,"dName":"[2009] Scenario 4 DB","dYear":"2009","dId":8}},{"sIndex":11,"sItem":{"cName":"ABC Partners","cId":0,"pName":"[ABC] ABC Partners","pTick":"ABC","pId":0,"dName":"[2009] Scenario 4 ExpResults DB","dYear":"2009","dId":9}},{"sIndex":12,"sItem":{"cName":"ABC Partners","cId":0,"pName":"[ABC] ABC Partners","pTick":"ABC","pId":0,"dName":"[2009] Scenario 5 DB","dYear":"2009","dId":10}},{"sIndex":13,"sItem":{"cName":"ABC Partners","cId":0,"pName":"[ABC] ABC Partners","pTick":"ABC","pId":0,"dName":"[2009] Scenario 5 ExpResults DB","dYear":"2009","dId":11}},{"sIndex":14,"sItem":{"cName":"ABC Partners","cId":0,"pName":"[ABC] ABC Partners","pTick":"ABC","pId":0,"dName":"[2010] Scenario 6 DB","dYear":"2010","dId":12}},{"sIndex":15,"sItem":{"cName":"ABC Partners","cId":0,"pName":"[ABC] ABC Partners","pTick":"ABC","pId":0,"dName":"[2010] Scenario 6 ExpResults DB","dYear":"2010","dId":13}},{"sIndex":16,"sItem":{"cName":"ABC Partners","cId":0,"pName":"[ABC] ABC Partners","pTick":"ABC","pId":0,"dName":"[2009] Scenario 7 DB","dYear":"2009","dId":14}},{"sIndex":17,"sItem":{"cName":"ABC Partners","cId":0,"pName":"[ABC] ABC Partners","pTick":"ABC","pId":0,"dName":"[2009] Scenario 7 ExpResults DB","dYear":"2009","dId":15}},{"sIndex":18,"sItem":{"cName":"ABC Partners","cId":0,"pName":"[ABC] ABC Partners","pTick":"ABC","pId":0,"dName":"[2009] Scenario 8 BaseDB","dYear":"2009","dId":16}},{"sIndex":19,"sItem":{"cName":"ABC Partners","cId":0,"pName":"[ABC] ABC Partners","pTick":"ABC","pId":0,"dName":"[2009] Scenario 8 DB","dYear":"2009","dId":17}},{"sIndex":20,"sItem":{"cName":"ABC Partners","cId":0,"pName":"[ABC] ABC Partners","pTick":"ABC","pId":0,"dName":"[2009] Scenario 8 ExpResults DB","dYear":"2009","dId":18}}]

函数应该返回第二个和第三个节点

如果输入搜索词：“ABC pa”，则函数应返回所有三个节点

很抱歉，这个问题很简短，如果您有任何帮助，我们将不胜感激。

步骤

• 按空格将搜索输入拆分为单词数组
• 使用该方法筛选源阵列
• 循环浏览源数组每个项的

  sItem

  属性，并：
  • 查看属性是否为

    字符串，以及是否为true
    
    循环搜索单词，查看是否在该属性中找到它们
    

• 如果在属性中找到了所有单词，则将true返回到

  过滤器

  方法

代码

您将搜索输入与什么进行比较？cName还是pName？因为第一个fresult没有pName，第二个和第三个结果的pName中只有“2014”，但第二个结果不包含“Partners”。因此，我不知道您想如何将“ABC pa 2014”与第二条和第三条记录相匹配。为什么

“ABC pa 2014”

与第二条和第三条记录相匹配，而不是第一条记录？据推测，2014年以来不在其中，但我假设atm问题中存在缺陷。一个非常简单的解决方案：。但我想您需要使用JSON解析器。@不好意思，我已经更新了JSON。我想首先匹配：cName和dYear，如果这不存在，我想匹配pTick和dYear。然后，我想通过任何给定的排列进行匹配。在返回第二个和第三个之后，我将返回第三个（and或rest）。但是，当我搜索“2009”时，也会返回“2010”。建议？我有一个pYear 2010和2009的数据集。@XiaoKan也用这些值编辑你的问题，这样我就可以在这里测试它们，看看发生了什么。而且，如果我的答案对你有用，即使它不是你所需要的，你至少可以投票：）对不起，我试图投票，但仍然是这个网站的新手，不让我。但是，我会确保这一点得到支持：）。谢谢@这是因为我在

filter

方法之外创建

found

数组，然后在另一次迭代中保持它的值。我已将其位置更改为方法内部，现在一切正常！我已经编辑了我的答案，所以你可以检查它！请，如果对你有用的话，你可以把答案标记为已接受的答案。非常感谢。非常感谢你。这真是太棒了。我已表示接受我的回答。我还有一个要求。而不是我将返回的数组排序到该函数之外。在返回数组之前，是否可以按数组中的dName降序对数组进行排序？你的帮助是无价的！

function search(val) {
  val = val.split(' '); // Step 1
  var filtered = arr.filter(function(item) { // Step 2
    var found = []; // Array to save how many words were found
    for (var prop in item.sItem) { // Step 3
      if (typeof item.sItem[prop] === 'string') { // Step 3.1
        for (var i = 0; i < val.length; i++) { // Step 3.1.1
          // Look if the current property has any of the words of the search input
          if (item.sItem[prop].toLowerCase().indexOf(val[i].toLowerCase()) >= 0) {
            found[i] = true; // if found, save to the found array
          }
        }
      }
    }

    // if the true values of the found array has the same length of the input search array
    return found.filter(function(expr) { return expr; }).length == val.length; // Step 4
  });

  // sort the filtered array by the dName property and return it
  return filtered.sort(function(a, b) {
    return b.sItem.dName > a.sItem.dName;
  });
}