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Javascript 不使用PHP和Ajax保存表单详细信息_Javascript_Php_Ajax - Fatal编程技术网

Javascript 不使用PHP和Ajax保存表单详细信息

Javascript 不使用PHP和Ajax保存表单详细信息,javascript,php,ajax,Javascript,Php,Ajax,我是PHP以及Ajax编程语言的初学者。我使用PHP和Ajax将一些数据存储到mysqli数据库中,不幸的是它没有保存,而是验证了每个数据 这是我做的代码段,但没有结果: <script> function sendContact() { var valid; valid = validateContact(); if (valid) {

我是
PHP
以及
Ajax
编程语言的初学者。我使用
PHP
Ajax
将一些数据存储到
mysqli
数据库中,不幸的是它没有保存,而是验证了每个数据

这是我做的代码段,但没有结果:

 <script>
    function sendContact() {
                var valid;
                valid = validateContact();
                if (valid) {


                    $('#Register').click(function (e) {

                        var username = $('#username').val();
                        var email = $('#email').val();
                        var password = $('#password').val();
                        var password1 = $('#password1').val();


                        var data = { "username": username, "email": email, "password": password, "password1": password1 };

                        jQuery.ajax({
                            data: data,
                            url: "phpquery/insert_patient.php", // Url to which the request is send
                            type: "POST",             // Type of request to be send, called as method

                            success: function (data) {

                                $('#username').val('');
                                $('#email').val('');
                                $('#password').val('');
                                $('#password1').val('');

                            }
                        });



                    });


                }
            }



            function validateContact() {
                var valid = true;
                $(".demoInputBox").css('background-color', '');
                $(".info").html('');

                if (!$("#username").val()) {
                    $("#userName-info").html("(required)");
                    $("#username").css('background-color', '#FFFFDF');
                    valid = false;
                }



                if (!$("#email").val()) {
                    $("#userEmail-info").html("(required)");
                    $("#email").css('background-color', '#FFFFDF');
                    valid = false;
                }
                if (!$("#email").val().match(/^([\w-\.]+@([\w-]+\.)+[\w-]{2,4})?$/)) {
                    $("#userEmail-info").html("(invalid)");
                    $("#email").css('background-color', '#FFFFDF');
                    valid = false;
                }
                if (!$("#password").val()) {
                    $("#password-info").html("(required)");
                    $("#password").css('background-color', '#FFFFDF');
                    valid = false;
                }
                if (!$("#password1").val()) {
                    $("#password1-info").html("(required)");
                    $("#password1").css('background-color', '#FFFFDF');
                    valid = false;
                }

                return valid;
            }

        </script>

函数sendContact(){
var有效;
valid=validateContact();
如果(有效){
$(“#寄存器”)。单击(函数(e){
var username=$('#username').val();
var email=$('#email').val();
var password=$('#password').val();
var password1=$('#password1').val();
var data={“用户名”:用户名,“电子邮件”:电子邮件,“密码”:密码,“密码1”:密码1};
jQuery.ajax({
数据:数据,
url:“phpquery/insert_patient.php”,//请求发送到的url
类型:“POST”,//要发送的请求类型,称为方法
成功:功能(数据){
$('#username').val('');
$('#email').val('');
$('#password').val('');
$('#password1').val('');
}
});
});
}
}
函数validateContact(){
var valid=true;
$(“.demoInputBox”).css('背景色','');
$(“.info”).html(“”);
如果(!$(“#用户名”).val()){
$(“#用户名信息”).html(“(必需)”);
$(“#username”).css('background-color','#FFFFDF');
有效=错误;
}
如果(!$(“#电子邮件”).val()){
$(“#用户电子邮件信息”).html(“(必需)”);
$(“#email”).css('background-color','#FFFFDF');
有效=错误;
}
如果(!$(“#email”).val().match(/^([\w-\.]+@([\w-]+\.)+[\w-]{2,4})?$/){
$(“#用户电子邮件信息”).html(“(无效)”);
$(“#email”).css('background-color','#FFFFDF');
有效=错误;
}
if(!$(“#密码”).val(){
$(“#密码信息”).html(“(必需)”);
$(“#password”).css('background-color','#FFFFDF');
有效=错误;
}
if(!$(“#password1”).val()){
$(“#password1 info”).html(“(必需)”);
$(“#password1”).css('background-color','#FFFFDF');
有效=错误;
}
返回有效;
}
下面是我的HTML代码:

<form name="poster" id="poster" method="post" class="s12" data-toggle="validator">
                        <div>
                            <div class="input-field s12">
                                <input type="text" id="username" name="username" data-ng-model="name1" class="validate"
                                    required>
                                <label>User name</label>
                                <span id="userName-info" class="text-danger"></span><br />

                            </div>
                        </div>
                        <div>
                            <div class="input-field s12">
                                <input type="email" id="email" name="email" class="validate" onblur="checkemail();"
                                    onkeyup="checkemail();" onchange="checkemail();" required>
                                <label>Email id</label>
                                <span id="userEmail-info" class="info"></span><br />

                                <span id="email_status" name="email_status"></span>

                            </div>
                        </div>
                        <div>
                            <div class="input-field s12">
                                <input type="password" name="password" id="password" class="validate" required>
                                <label>Password</label>
                                <span id="password-info" class="text-danger"></span><br />

                            </div>
                        </div>
                        <div>
                            <div class="input-field s12">
                                <input type="password" name="password1" id="password1" class="validate" required>
                                <label>Confirm password</label>
                                <span id="password1-info" class="text-danger"></span><br />

                            </div>
                        </div>



                        <div>
                            <div class="input-field s4">


                                <input type="button" value="Register" id="Register" name="Register"
                                    class="waves-effect waves-light log-in-btn" onClick="sendContact();">
                            </div>
                        </div>





                        <div>
                            <div class="input-field s12">                    
                  <a href="#" data-dismiss="modal" data-toggle="modal"
                                    data-target="#modal1">Are you a already member ? Login</a> </div>
                        </div>
                    </form>

用户名

电子邮件id
暗语
确认密码
我的insert_patient.php页面将是:

    <?php
    // include('colour.css');
    include('dbconnection.php');

    if (isset($_POST['username'])) {

      $first_name="";
      $last_name="";
      $address="";
      $gender="";
      $dob="";
      $contact="";
      $state="";
      $image="";
      $note="";

      $username=$_POST["username"];
      $email=$_POST["email"];
      $password=$_POST["password"];





$sql= "INSERT INTO patients (p_fname,p_lname,p_address,p_gender,dob,p_contact,p_state,username,email,password,image,note) 
      VALUES ('". $first_name."','". $last_name."','". $address."', '". $gender."','". $dob."','". $contact."', '". $state."','". $username."','". $email."', '". $password."' , '". $image."', '". $note."')  ";

      if(mysqli_query($con,$sql) ){
        echo'save';

      }
      else {
        echo 'fail';
      }

      }

sendContact
应该只执行AJAX调用,而不应该调用
$(“#注册”)。单击()。这为下次单击按钮添加了一个事件处理程序,它不会发送AJAX请求

function sendContact() {
  var valid;
  valid = validateContact();
  if (valid) {
    var username = $('#username').val();
    var email = $('#email').val();
    var password = $('#password').val();
    var password1 = $('#password1').val();
    var data = {
      "username": username,
      "email": email,
      "password": password,
      "password1": password1
    };

    jQuery.ajax({
      data: data,
      url: "phpquery/insert_patient.php", // Url to which the request is send
      type: "POST", // Type of request to be send, called as method

      success: function(data) {
        $('#username').val('');
        $('#email').val('');
        $('#password').val('');
        $('#password1').val('');
      }
    });
  });
}

它是否返回
保存
失败
?如果查询失败,您应该使用
mysqli\u error($con)
来找出原因。您应该学习如何使用准备好的语句来防止SQL注入。@Barmar这里是关于Ajax查询的问题。未经验证,它正在保存..确保jQuery库(JS)已加载。看看您的开发人员控制台。
c=“ajax/vendor.js”>
我认为最好从代码段中取出它。信息技术他在工作。代码上没有错误。