Javascript 为什么.then（）在promise实际解决之前就被解雇了？

我正在尝试从异步任务返回承诺，以便使用.then（）调用使它们同步。不幸的是，我正在经历一些真正奇怪的行为。基本上，第三个then（）在第二个问题解决之前执行。有人能解释一下发生了什么事吗？这是我的密码：

function runReleaseLoop() {
  console.log('Starting release loop');
  const themes = ['blue', 'red'];
  return new Promise(resolve => {
    buildReleases(themes, resolve);
  })
}

function buildReleases(themes, onComplete) {
  console.log(themes);
  if (themes.length === 0) {
    onComplete();
  } else {
    const theme = themes.pop();
    Promise.resolve()
      .then(setTheme(theme))
      .then(someDelayedTask(theme))
      .then(buildReleases(themes, onComplete));
  }
}

function setTheme(theme) {
  return new Promise(resolve => {
    console.log(`Setting theme to ${theme}`);
    resolve();
  });
}

function someDelayedTask(theme) {
  console.log(`Starting delayed task related to ${theme}`);
  return new Promise(resolve => {
    setTimeout(() => {
      console.log(`Finished delayed task related to ${theme}`);
      resolve();
    }, 3000)
  });
}

// Run the process
runReleaseLoop()
  .then(() => {
    console.log('Release loop finished')
  });

以下是我的控制台输出：

"Starting release loop"
["blue", "red"]
"Setting theme to red"
"Starting delayed task related to red"
["blue"]
"Setting theme to blue"
"Starting delayed task related to blue"
[]
"Release loop finished"
"Finished delayed task related to red"
"Finished delayed task related to blue"

---

您正在同步调用这些函数（

setTheme

，

someDelayedTask

，以及

buildReleases

），然后将它们的返回值（承诺）传递到

然后

，而不是将函数本身传递到：

Promise.resolve()
  .then(setTheme(theme))
  .then(someDelayedTask(theme))
  .then(buildReleases(themes, onComplete));

这里有一个解决方案：

Promise.resolve()
  .then(_ => setTheme(theme))
  .then(_ => someDelayedTask(theme))
  .then(_ => buildReleases(themes, onComplete));

以下是进行上述更改后的代码输出：

Starting release loop
[ 'blue', 'red' ]
Setting theme to red
Starting delayed task related to red
Finished delayed task related to red
[ 'blue' ]
Setting theme to blue
Starting delayed task related to blue
Finished delayed task related to blue
[]
Release loop finished

---

第一个问题是，你把承诺和回访混为一谈。第二个是一次性调用所有函数

setTheme、someDelayedTask、buildReleases

：

function runReleaseLoop() {
  console.log('Starting release loop');
  const themes = ['blue', 'red'];
  return buildReleases(themes);
}

function buildReleases(themes) {
  console.log(themes);
  if (themes.length === 0) {
    return Promise.resolve();
  }

  const theme = themes.pop();
  return setTheme(theme)
    .then(() => someDelayedTask(theme))
    .then(() => buildReleases(themes));
}

function setTheme(theme) {
  console.log(`Setting theme to ${theme}`);
}

function someDelayedTask(theme) {
  console.log(`Starting delayed task related to ${theme}`);
  return new Promise(resolve => {
    setTimeout(() => {
      console.log(`Finished delayed task related to ${theme}`);
      resolve();
    }, 3000)
  });
}

// Run the process
runReleaseLoop()
  .then(() => console.log('Release loop finished'));

---

因此，对于接受参数的函数，我需要返回一个返回承诺的函数？是的，正确（oops删除了第一条注释lol），但是您还需要按照返回的承诺执行操作，等等。您还可以执行以下操作：promise.resolve（）.then（setTheme）。然后（someDelayedTask）。然后（buildReleases）；