Javascript 如何拆分任何url并仅获取源？_Javascript_Regex_Split

Javascript 如何拆分任何url并仅获取源？

javascript regex

Javascript 如何拆分任何url并仅获取源？,javascript,regex,split,Javascript,Regex,Split,我想拆分https://abcnews.go.com/此类型的URL 想获得abcnews 我用过： .split('//')[1] .split('www.')[1] .split('.com')[0] .split('.org')[0] .split('.edu')[0] .split('.info')[0] 我得到的错误不能分割你知道怎么做吗？你接受Regex的回答吗 consturl='1〕https://abcnews.go.com/'; 让子域=url.match（/（\w*）

我想拆分

https://abcnews.go.com/

此类型的URL

想获得abcnews
我用过：

.split('//')[1] .split('www.')[1] .split('.com')[0] .split('.org')[0] .split('.edu')[0] .split('.info')[0]
我得到的错误不能分割

你知道怎么做吗？
你接受Regex的回答吗

consturl='1〕https://abcnews.go.com/'; 让子域=url.match（/（\w*）\./）[1]； console.log（子域） //subdomain=“abcnews”
您接受Regex的回复吗

consturl='1〕https://abcnews.go.com/'; 让子域=url.match（/（\w*）\./）[1]； console.log（子域） //subdomain=“abcnews”
这看起来很安全：

(?:https?:\/\/(?:www\.)?|www\.)([^.\/]+)
看
解释

-------------------------------------------------------------------------------- (?: group, but do not capture: -------------------------------------------------------------------------------- http 'http' -------------------------------------------------------------------------------- s? 's' (optional (matching the most amount possible)) -------------------------------------------------------------------------------- : ':' -------------------------------------------------------------------------------- \/ '/' -------------------------------------------------------------------------------- \/ '/' -------------------------------------------------------------------------------- (?: group, but do not capture (optional (matching the most amount possible)): -------------------------------------------------------------------------------- www 'www' -------------------------------------------------------------------------------- \. '.' -------------------------------------------------------------------------------- )? end of grouping -------------------------------------------------------------------------------- | OR -------------------------------------------------------------------------------- www 'www' -------------------------------------------------------------------------------- \. '.' -------------------------------------------------------------------------------- ) end of grouping -------------------------------------------------------------------------------- ( group and capture to \1: -------------------------------------------------------------------------------- [^.\/]+ any character except: '.', '\/' (1 or more times (matching the most amount possible)) -------------------------------------------------------------------------------- ) end of \1
JavaScript代码：

consturl=”https://abcnews.go.com/" 常量正则表达式=/（？：https？：\/\/（？：www\）？；www\）（[^.\/]+）/ const match=url.match（正则表达式）如果（匹配）{ console.log（匹配[1]） }
这看起来很安全：

(?:https?:\/\/(?:www\.)?|www\.)([^.\/]+)
看
解释

-------------------------------------------------------------------------------- (?: group, but do not capture: -------------------------------------------------------------------------------- http 'http' -------------------------------------------------------------------------------- s? 's' (optional (matching the most amount possible)) -------------------------------------------------------------------------------- : ':' -------------------------------------------------------------------------------- \/ '/' -------------------------------------------------------------------------------- \/ '/' -------------------------------------------------------------------------------- (?: group, but do not capture (optional (matching the most amount possible)): -------------------------------------------------------------------------------- www 'www' -------------------------------------------------------------------------------- \. '.' -------------------------------------------------------------------------------- )? end of grouping -------------------------------------------------------------------------------- | OR -------------------------------------------------------------------------------- www 'www' -------------------------------------------------------------------------------- \. '.' -------------------------------------------------------------------------------- ) end of grouping -------------------------------------------------------------------------------- ( group and capture to \1: -------------------------------------------------------------------------------- [^.\/]+ any character except: '.', '\/' (1 or more times (matching the most amount possible)) -------------------------------------------------------------------------------- ) end of \1
JavaScript代码：

consturl=”https://abcnews.go.com/" 常量正则表达式=/（？：https？：\/\/（？：www\）？；www\）（[^.\/]+）/ const match=url.match（正则表达式）如果（匹配）{ console.log（匹配[1]） }
s.match（/：\/\/（[^.\/]+）/）[1]
如果url有www.something.com，则我只收到www请根据您的所有要求更新问题。请尝试
（？：https？：\/\/（？：www\）？（www\）（[^.\/]+）/
，请参阅。
s.match（/：\/\/\/（[^.\/]+）/）[1]
如果url有www.something.com，那么我只会收到www请根据您的所有要求更新问题。请尝试
（？：https？：\/\/（？：www\.）？；www\.）（[^.\/]+）/
，请参阅。