Javascript 数组合并和Json编码

我生成的数组数量未知，如下所示：

for ($t=0;$t<2;$t++) {
  for ($xx=0;$xx<$totf[$t];$xx++) {
    $otdata[$t][$xx] = array("".$otname[$t][$xx]."" =>
        ['games'=> $otg[$t][$xx], 
        'mint'=> $otqmint[$t][$xx], 
        'pct'=>$otpct[$t][$xx]]);
  }
}

$newot= array_merge_recursive($otfdata);
$myJsondata = json_encode($newot);
file_put_contents('json/myJson.json', $myJsondata);

[[{"John":{"games":"1","mint":"3.65","pct":"0"}},
{"Mary":{"games":"1","mint":"0.625","pct":"12"}},
...
{"Whatever":{"games":"1","mint":"0.325","pct":"4"}}]]

{"John":{"games":"1","mint":"3.65","pct":"0"},
"Mary":{"games":"1","mint":"0.625","pct":"12"},
...
"Whatever":{"games":"1","mint":"0.325","pct":"4"}}

生成的

myJson.json

文件如下所示：

for ($t=0;$t<2;$t++) {
  for ($xx=0;$xx<$totf[$t];$xx++) {
    $otdata[$t][$xx] = array("".$otname[$t][$xx]."" =>
        ['games'=> $otg[$t][$xx], 
        'mint'=> $otqmint[$t][$xx], 
        'pct'=>$otpct[$t][$xx]]);
  }
}

$newot= array_merge_recursive($otfdata);
$myJsondata = json_encode($newot);
file_put_contents('json/myJson.json', $myJsondata);

[[{"John":{"games":"1","mint":"3.65","pct":"0"}},
{"Mary":{"games":"1","mint":"0.625","pct":"12"}},
...
{"Whatever":{"games":"1","mint":"0.325","pct":"4"}}]]

{"John":{"games":"1","mint":"3.65","pct":"0"},
"Mary":{"games":"1","mint":"0.625","pct":"12"},
...
"Whatever":{"games":"1","mint":"0.325","pct":"4"}}

我不知道如何管理这个文件。我是说，我想这样做：

for ($t=0;$t<2;$t++) {
  for ($xx=0;$xx<$totf[$t];$xx++) {
    $otdata[$t][$xx] = array("".$otname[$t][$xx]."" =>
        ['games'=> $otg[$t][$xx], 
        'mint'=> $otqmint[$t][$xx], 
        'pct'=>$otpct[$t][$xx]]);
  }
}

$newot= array_merge_recursive($otfdata);
$myJsondata = json_encode($newot);
file_put_contents('json/myJson.json', $myJsondata);

[[{"John":{"games":"1","mint":"3.65","pct":"0"}},
{"Mary":{"games":"1","mint":"0.625","pct":"12"}},
...
{"Whatever":{"games":"1","mint":"0.325","pct":"4"}}]]

{"John":{"games":"1","mint":"3.65","pct":"0"},
"Mary":{"games":"1","mint":"0.625","pct":"12"},
...
"Whatever":{"games":"1","mint":"0.325","pct":"4"}}

1） 在php中，我希望达到“mint”数据点“Mary”=>“0.625”

显然，这是行不通的

2） 在jQuery中，我希望基本相同：达到“mint”数据点“Mary”

我的问题：

A） 我认为我遇到的第一个问题是在合并不同阵列的过程中。我这样做会在开始和结束时生成

[[

，我认为这是不正确的

B） 除此之外，我在jQuery中的做法正确吗

我需要的是：

1） 要以如下方式合并和编码阵列：

for ($t=0;$t<2;$t++) {
  for ($xx=0;$xx<$totf[$t];$xx++) {
    $otdata[$t][$xx] = array("".$otname[$t][$xx]."" =>
        ['games'=> $otg[$t][$xx], 
        'mint'=> $otqmint[$t][$xx], 
        'pct'=>$otpct[$t][$xx]]);
  }
}

$newot= array_merge_recursive($otfdata);
$myJsondata = json_encode($newot);
file_put_contents('json/myJson.json', $myJsondata);

[[{"John":{"games":"1","mint":"3.65","pct":"0"}},
{"Mary":{"games":"1","mint":"0.625","pct":"12"}},
...
{"Whatever":{"games":"1","mint":"0.325","pct":"4"}}]]

{"John":{"games":"1","mint":"3.65","pct":"0"},
"Mary":{"games":"1","mint":"0.625","pct":"12"},
...
"Whatever":{"games":"1","mint":"0.325","pct":"4"}}

我认为这将解决问题A

2） 确认我在jQuery中的操作方式是否正确

---

谢谢

您可以按如下所示的预期格式生成数组

<?php

$data = array();

for ($t=0;$t<2;$t++) {
  for ($xx=0;$xx<$totf[$t];$xx++) {

    //create the temporary array
    $temp = array(
        'games'=> $otg[$t][$xx], 
        'mint'=> $otqmint[$t][$xx], 
        'pct'=>$otpct[$t][$xx]]
    );

    //identify the array key
    $key = $otname[$t][$xx];

    //check the key is exist or not
    if(isset($data[$key])) {

        //take the existing value as a backup
        $exone = $data[$key]; 
        //overwrite the array
        $data[$key] = array();

        //check the exsiting array is multidimension or not
        if(isset($exone[0])) {
            foreach ($exone as $one) {
                //push the array to the respective key
                array_push($data[$key], $one);
            }
        }
        else {
            //if single dimension then make it multi dimension
            array_push($data[$key], $exone);            
        }

        //push the latest array to the same key
        array_push($data[$key], $temp);

    }//create the new array for the key
    else {          
        $data[$key] = $temp;
    }

    /*$otdata[$t][$xx] = array("".$otname[$t][$xx]."" =>
        ['games'=> $otg[$t][$xx], 
        'mint'=> $otqmint[$t][$xx], 
        'pct'=>$otpct[$t][$xx]]);
    }
*/}

//print the json data
echo json_encode($data);

---

array\u merge\u recursive-递归合并两个或多个数组array\u merge\u recursive是我正在使用的。数组键中有不同的名称，这就是为什么要得到
嵌套数组的原因，即数组检查示例。我不明白你的意思。你如何改变我构建数组的方式r我合并它们的方式？太好了！非常感谢。