如何使用javascript旋转多个图像？

我遵循本教程，本教程只适用于单个图像。多张图片怎么样？有什么想法吗

我有如下javascript代码：

 var img = null, canvas = null;

$(document).ready(function(){
   //  Initialize image and canvas
   img = document.getElementById('image');
   canvas = document.getElementById('canvas');

   if(!canvas || !canvas.getContext){
       canvas.parentNode.removeChild(canvas);
   } else {
       img.style.position = 'absolute';
       img.style.visibility = 'hidden';
   }
   rotateImage(0);

   //  Handle clicks for control links
   $('#resetImage').click(function(){ rotateImage(0); });
   $('#rotate90').click(function(){ rotateImage(90); });
   $('#rotate180').click(function(){ rotateImage(180); });
   $('#rotate270').click(function(){ rotateImage(270); });
});

function rotateImage(degree)
{
    if(document.getElementById('canvas')){
       var cContext = canvas.getContext('2d');
       var cw = img.width, ch = img.height, cx = 0, cy = 0;

       //   Calculate new canvas size and x/y coorditates for image
       switch(degree){
            case 90:
                cw = img.height;
                ch = img.width;
                cy = img.height * (-1);
                break;
            case 180:
                cx = img.width * (-1);
                cy = img.height * (-1);
                break;
            case 270:
                cw = img.height;
                ch = img.width;
                cx = img.width * (-1);
                break;
       }

        //  Rotate image            
        canvas.setAttribute('width', cw);
        canvas.setAttribute('height', ch);
        cContext.rotate(degree * Math.PI / 180);
        cContext.drawImage(img, cx, cy);
    } else {
        //  Use DXImageTransform.Microsoft.BasicImage filter for MSIE
        switch(degree){
            case 0: image.style.filter = 'progid:DXImageTransform.Microsoft.BasicImage(rotation=0)'; break;
            case 90: image.style.filter = 'progid:DXImageTransform.Microsoft.BasicImage(rotation=1)'; break;
            case 180: image.style.filter = 'progid:DXImageTransform.Microsoft.BasicImage(rotation=2)'; break;
            case 270: image.style.filter = 'progid:DXImageTransform.Microsoft.BasicImage(rotation=3)'; break;
        }
    }
}

<div><!-- my html code -->
        <img src="image/a.png" alt="" id="image" />
        <canvas id="canvas"></canvas>
    </div>
    <p>
        <strong>Rotate Image: </strong>
        <a href="javascript:;" id="resetImage">Reset Image</a>
        <a href="javascript:;" id="rotate90">90&deg;</a>
        <a href="javascript:;" id="rotate180">180&deg;</a>
        <a href="javascript:;" id="rotate270">270&deg;</a>
    </p>

我的html是这样的：

 var img = null, canvas = null;

$(document).ready(function(){
   //  Initialize image and canvas
   img = document.getElementById('image');
   canvas = document.getElementById('canvas');

   if(!canvas || !canvas.getContext){
       canvas.parentNode.removeChild(canvas);
   } else {
       img.style.position = 'absolute';
       img.style.visibility = 'hidden';
   }
   rotateImage(0);

   //  Handle clicks for control links
   $('#resetImage').click(function(){ rotateImage(0); });
   $('#rotate90').click(function(){ rotateImage(90); });
   $('#rotate180').click(function(){ rotateImage(180); });
   $('#rotate270').click(function(){ rotateImage(270); });
});

function rotateImage(degree)
{
    if(document.getElementById('canvas')){
       var cContext = canvas.getContext('2d');
       var cw = img.width, ch = img.height, cx = 0, cy = 0;

       //   Calculate new canvas size and x/y coorditates for image
       switch(degree){
            case 90:
                cw = img.height;
                ch = img.width;
                cy = img.height * (-1);
                break;
            case 180:
                cx = img.width * (-1);
                cy = img.height * (-1);
                break;
            case 270:
                cw = img.height;
                ch = img.width;
                cx = img.width * (-1);
                break;
       }

        //  Rotate image            
        canvas.setAttribute('width', cw);
        canvas.setAttribute('height', ch);
        cContext.rotate(degree * Math.PI / 180);
        cContext.drawImage(img, cx, cy);
    } else {
        //  Use DXImageTransform.Microsoft.BasicImage filter for MSIE
        switch(degree){
            case 0: image.style.filter = 'progid:DXImageTransform.Microsoft.BasicImage(rotation=0)'; break;
            case 90: image.style.filter = 'progid:DXImageTransform.Microsoft.BasicImage(rotation=1)'; break;
            case 180: image.style.filter = 'progid:DXImageTransform.Microsoft.BasicImage(rotation=2)'; break;
            case 270: image.style.filter = 'progid:DXImageTransform.Microsoft.BasicImage(rotation=3)'; break;
        }
    }
}

<div><!-- my html code -->
        <img src="image/a.png" alt="" id="image" />
        <canvas id="canvas"></canvas>
    </div>
    <p>
        <strong>Rotate Image: </strong>
        <a href="javascript:;" id="resetImage">Reset Image</a>
        <a href="javascript:;" id="rotate90">90&deg;</a>
        <a href="javascript:;" id="rotate180">180&deg;</a>
        <a href="javascript:;" id="rotate270">270&deg;</a>
    </p>

旋转图像：

---

这是一个很好的工作在单一的形象，有任何想法，为运行多个形象呢？我应该怎么做？

这会有点棘手，但使用jQuery，您应该能够做到这一点。您需要将大部分id更改为类。为每个设置一个画布。您必须将单击事件“e”传递给函数（e），然后传递给旋转图像（e，度）。然后，您需要获取离按钮最近的图像，以便知道要更改的图像。对不起，我没有时间写代码。可能吗？当我用php显示图像时，图像id和文件名相同，如何在javascript中访问它？为多个idif创建数组变量如果您可以解决此问题，请帮助我。我是javascript的新手