Javascript 捕获段落中的所有问题

我一直在尝试使用Javascript的正则表达式来解析给定段落中的每个问题。但是，我得到了不想要的结果：

Javascript

regex = /(\S.+?[.!?])(?=\s+|$)/g;
result = regex.exec("I can see you. Where are you? I am here! How did you get there?");

["Where are you?", "How did you get there?"]

["I can see you.", "I can see you."]

预期结果

regex = /(\S.+?[.!?])(?=\s+|$)/g;
result = regex.exec("I can see you. Where are you? I am here! How did you get there?");

["Where are you?", "How did you get there?"]

["I can see you.", "I can see you."]

实际结果

regex = /(\S.+?[.!?])(?=\s+|$)/g;
result = regex.exec("I can see you. Where are you? I am here! How did you get there?");

["Where are you?", "How did you get there?"]

["I can see you.", "I can see you."]

附言：如果有更好的方法，我洗耳恭听

试试这个：

var x = string.match(/\(?[A-Z][^\.!\?]+[!\.\?]\)?/g);
x.filter(function(sentence) {
  return sentence.indexOf('?') >= 0;
})

试试这个：

var x = string.match(/\(?[A-Z][^\.!\?]+[!\.\?]\)?/g);
x.filter(function(sentence) {
  return sentence.indexOf('?') >= 0;
})

---

JavaScript正则表达式选项的

.exec

方法仅返回与捕获的第一个匹配项。它还使用匹配字符串中的位置更新regex对象。这就是允许您使用

.exec

方法循环遍历字符串的原因（也是您仅获得第一个匹配项的原因）

尝试改用字符串对象的

.match

方法：

regex = /(\S.+?[.!?])(?=\s+|$)/g;
result = ("I can see you. Where are you? I am here! How did you get there?").match(regex);

这将产生以下预期结果：

[
    "I can see you.",
    "Where are you?",
    "I am here!",
    "How did you get there?"
]

---

JavaScript正则表达式选项的

.exec

方法仅返回与捕获的第一个匹配项。它还使用匹配字符串中的位置更新regex对象。这就是允许您使用

.exec

方法循环遍历字符串的原因（也是您仅获得第一个匹配项的原因）

尝试改用字符串对象的

.match

方法：

regex = /(\S.+?[.!?])(?=\s+|$)/g;
result = ("I can see you. Where are you? I am here! How did you get there?").match(regex);

这将产生以下预期结果：

[
    "I can see you.",
    "Where are you?",
    "I am here!",
    "How did you get there?"
]

输出：

[ 'Where are you?',
  'How did you get there?' ]

输出：

[ 'Where are you?',
  'How did you get there?' ]

---

不客气，你为什么要换答案？功能上是一样的afaik，虽然新的是一个稍微短一点的正则表达式。我发现你的过滤器和短一点的正则表达式相结合是最好的方法。我希望我能选择两者都是最好的：）不用担心，谢谢，只是确保我没有错过一些微妙的问题。不客气，你有什么理由交换答案吗？功能上是一样的afaik，虽然新的是一个稍微短一点的正则表达式。我发现你的过滤器和短一点的正则表达式相结合是最好的方法。我希望我能选择两者都是最好的：）不用担心，谢谢，只是确保我没有错过一些微妙的问题。