Javascript 允许1-9和破折号正则表达式
这将允许用户输入a-z，但如何添加0-9和破折号<代码>/^[a-zA-Z\s]*$/Javascript 允许1-9和破折号正则表达式,javascript,regex,Javascript,Regex,这将允许用户输入a-z，但如何添加0-9和破折号/^[a-zA-Z\s]*$/ /^[a-zA-Z\d\s-]*$/ 字符类（[]）末尾的破折号不需要转义，否则使用\- 要匹配数字，您可以使用0-9或简单地使用\d，具体取决于您的正则表达式风格 正则表达式解释： ^[a-zA-Z\d\s-]*$ Assert position at the beginning of a line (at beginning of the string or after a line break chara
/^[a-zA-Z\d\s-]*$/
[]\-0-9\d正则表达式解释：
^[a-zA-Z\d\s-]*$
Assert position at the beginning of a line (at beginning of the string or after a line break character) (line feed) «^»
Match a single character present in the list below «[a-zA-Z\d\s-]*»
Between zero and unlimited times, as many times as possible, giving back as needed (greedy) «*»
A character in the range between “a” and “z” (case insensitive) «a-z»
A character in the range between “A” and “Z” (case insensitive) «A-Z»
A “digit” (any decimal number in any Unicode script) «\d»
A “whitespace character” (any Unicode separator, tab, line feed, carriage return, vertical tab, form feed, next line) «\s»
The literal character “-” «-»
Assert position at the end of a line (at the end of the string or before a line break character) (line feed) «$»
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/^[1-9-]*$/var reg = new RegExp("^[1-9-]*$");
var s = '1234-5678';
if (reg.exec(s)) {
console.log("Match\n");
} else {
console.log("No match\n");
}
是否允许用户输入[空白]？是否阅读了有关如何使用正则表达式的教程？因为这是非常普遍的和基本的。你是说涵盖0-9还是1-9，问题的标题和上下文各不相同。@SpencerWieczorek我只是不知道把
-\s\s@“[空白字符]@”\s-后面的第一个字符中吗[=~$s