在For循环中重新分配列表（JavaScript）

如果以前有人问过我，我很抱歉——我在搜索后找不到我想要的东西，但我是个初学者，所以我可能错过了一些东西

我试图用JavaScript实现Lloyd的算法（非常粗糙），以获得一些实践

var k_means = function (array,number_clusters,max_loops) {
  var initial_centers = underscore.sample(shelter_lat_lon,number_clusters);
  var current_centers = initial_centers;

  var current_associations = {};
  for (p = 0; p < current_centers.length; p++) {
      current_associations[current_centers[p]] = []
  }

  for (loops = 0; loops < max_loops; loops++) {
    for (i = 0; i < array.length; i++) {
      var current_loc = array[i]
      temp_array = new Array();
      for (j = 0; j < current_centers.length; j++) {
        var distance_from_center = distance(current_centers[j],current_loc)
        temp_array.push(distance_from_center)
      }
      var closest_center_lat_lon = current_centers[smallest_index(temp_array)]
      current_associations[closest_center_lat_lon].push(current_loc)
    }
    new_clusters_temp = []
    for (var key in current_associations) {
      lat = []
      lon = []
      for (i = 0; i < current_associations[key].length; i++){
        lat.push(current_associations[key][i][0])
        lon.push(current_associations[key][i][1])
      }
      mean_lat = math_module.mean(lat)
      mean_lon = math_module.mean(lon)
      new_clusters_temp.push([mean_lat,mean_lon])
    }
    current_centers = new_clusters_temp;
  }
}

节点返回错误“无法读取未定义的属性‘push’”。调试一段时间后，它本质上认为数组“current_centers”为空。在Python中，这就是我在for循环之外重新分配列表的方式。这在JavaScript中不同吗

干杯！

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Alex

您需要做的第一件事是修复for循环。对于（u=0；ucurrent_centers = new_clusters_temp;