Javascript 如何在React中从查询选择器工作到useRef?
我有一个打字效果函数。现在我想向代码显示div typingRef中的效果,我制作了类似于typingRef.current=letter的东西,但这与document.queryselector'typing.textContent=letter相同吗?我想使用ref而不是queryselectorJavascript 如何在React中从查询选择器工作到useRef?,javascript,reactjs,Javascript,Reactjs,我有一个打字效果函数。现在我想向代码显示div typingRef中的效果,我制作了类似于typingRef.current=letter的东西,但这与document.queryselector'typing.textContent=letter相同吗?我想使用ref而不是queryselector 我能想出的最好办法就是试着理解你的问题。试试这个:typingRef.current.innerHTML export const Text = ({ children }) => {
我能想出的最好办法就是试着理解你的问题。试试这个:typingRef.current.innerHTML
export const Text = ({ children }) => {
const headingRef = React.useRef(null)
const typingRef = React.useRef(null)
const texts = ['websites', 'applications', 'mobile' ]
React.useEffect(() => {
let count = 0
let index = 0
let currentText = ''
let letter = ''
function type() {
if (count === texts.length) {
count = 0
}
currentText = texts[count]
letter = currentText.slice(0, ++index)
typingRef.current.innerHTML = letter
if (letter.length === currentText.length) {
count++
index = 0
}
setTimeout(type, 400)
}
type()
})
return (
<div>
<div>
<h1 ref={headingRef}>
{ children }
</h1>
<div ref={typingRef}/>
</div>
</div>
)
}
export const Text = ({ children }) => {
const headingRef = React.useRef(null)
const typingRef = React.useRef(null)
const texts = ['websites', 'applications', 'mobile' ]
React.useEffect(() => {
let count = 0
let index = 0
let currentText = ''
let letter = ''
function type() {
if (count === texts.length) {
count = 0
}
currentText = texts[count]
letter = currentText.slice(0, ++index)
typingRef.current.innerHTML = letter
if (letter.length === currentText.length) {
count++
index = 0
}
setTimeout(type, 400)
}
type()
})
return (
<div>
<div>
<h1 ref={headingRef}>
{ children }
</h1>
<div ref={typingRef}/>
</div>
</div>
)
}