Javascript AJAX响应，用于循环难度

我有个小问题。也就是说，我想得到我的变量的值：count_green在for循环之外。有人知道我怎么做吗？ 以下是我的代码片段：

function State(type, count, list_name){
var count_green = 0;
var count_yellow = 0;
var count_red = 0;

for (i = 0; i < count; i++){
    var jqxhr = $.ajax( "/custom_data/getState/" + type[i]).done(function(result) {
        for (j = 0; j < count; j++){
            if(result.type == type[j]){
                if(result.value == "GREEN"){
                    $("#" + type[j]).css("color","#468847");
                    count_green = count_green + 1;
                }
                if(result.value == "YELLOW"){
                    $("#" + type[j]).css("color","#f89406");
                    count_yellow = count_yellow + 1; 
                }
                if(result.value == "RED"){
                    $("#" + type[j]).css("color","#b94a48");
                    count_red = count_red + 1;
                }
            }
        }
    });
}
    //Here I would need the value of count_green, count_yellow and count_green
    //Unfortunately they are outside of the for loop 0.
    addCounters(count_green, count_yellow, count_red);
}

function addCounters(state_green, state_yellow, state_red){
    $(".line").find(".list").append('<span class="badge pull-left count_badge badge-success">' + state_green + '</span>');
}

功能状态（类型、计数、列表名称）{
var count_green=0；
var count_yellow=0；
风险值计数=0；
对于（i=0；i

如您所见，如果我将方法调用addCounters放入for循环中，我会得到许多徽章，说明为什么我需要访问count变量：count_green、count_yellow和count_red，它们位于for循环和ajax代码之外。 我看到了一些使用回调的解决方案，但我只需要变量值的一倍，如果我使用回调，我得到的值将超过1倍

---

提前感谢您。

一个解决方案是同步请求。看看async属性

$.ajax( "/custom_data/getState/" + type[i], {async: false}).done(...)

另一个解决方案是这样的

var requestCount = 0;

for (i = 0; i < count; i++){
    var jqxhr = $.ajax( "/custom_data/getState/" + type[i]).done(function(result) {
        for (j = 0; j < count; j++){
            if(result.type == type[j]){
                if(result.value == "GREEN"){
                    $("#" + type[j]).css("color","#468847");
                    count_green = count_green + 1;
                }
                if(result.value == "YELLOW"){
                    $("#" + type[j]).css("color","#f89406");
                    count_yellow = count_yellow + 1;
                }
                if(result.value == "RED"){
                    $("#" + type[j]).css("color","#b94a48");
                    count_red = count_red + 1;
                }
            }
        }
        requestFinished(count_green, count_yellow, count_red);
    });
}

function requestFinished(count_green, count_yellow, count_red){
    requestCount++;
    if(requestCount == count){//all requests finished
       addCounters(count_green, count_yellow, count_red);
    }
}

var requestCount=0；
对于（i=0；i

嗨，michael，谢谢您的回复。还有其他解决办法吗？