Javascript 如何使此功能正常工作?
当我运行此命令时,我得到一个错误:getInfo未定义。那么,我该如何做到这一点呢 (我知道这不是一个安全登录,我现在不担心) 这个怎么样:Javascript 如何使此功能正常工作?,javascript,jquery,Javascript,Jquery,当我运行此命令时,我得到一个错误:getInfo未定义。那么,我该如何做到这一点呢 (我知道这不是一个安全登录,我现在不担心) 这个怎么样: function getInfo(){ var user = document.getElementById('username'); var username = user.value; var pass = document.getElementById('password'); var password = pass.
function getInfo(){
var user = document.getElementById('username');
var username = user.value;
var pass = document.getElementById('password');
var password = pass.value;
return [username, password];
});
document.getElementById("submit").addEventListener("click", function (){ getInfo();});
//or
//document.getElementById("submit").addEventListener("click", getInfo);
var userinfo = getInfo();
var username = userinfo[0];
var password = userinfo[1];
console.log(username, password);
或
document.getElementById(“提交”).addEventListener(“单击”,getInfo,false)代码>
function getInfo(){
var user = document.getElementById('username');
var username = user.value;
var pass = document.getElementById('password');
var password = pass.value;
return [username, password];
});
document.getElementById("submit").addEventListener("click", function (){ getInfo();});
//or
//document.getElementById("submit").addEventListener("click", getInfo);
var userinfo = getInfo();
var username = userinfo[0];
var password = userinfo[1];
console.log(username, password);