Warning: file_get_contents(/data/phpspider/zhask/data//catemap/9/javascript/440.json): failed to open stream: No such file or directory in /data/phpspider/zhask/libs/function.php on line 167

Warning: Invalid argument supplied for foreach() in /data/phpspider/zhask/libs/tag.function.php on line 1116

Notice: Undefined index: in /data/phpspider/zhask/libs/function.php on line 180

Warning: array_chunk() expects parameter 1 to be array, null given in /data/phpspider/zhask/libs/function.php on line 181
javascript中的trasform原点和比例_Javascript - Fatal编程技术网

javascript中的trasform原点和比例

javascript中的trasform原点和比例,javascript,Javascript,我需要替换此CSS代码: transform:scale(0,0); transform-origin: top left; 用javascript代码,但我不知道怎么做 我在找这样的东西: .style.opacity="0"; 谢谢 我有这样的想法: x.getElementsByTagName('img')[0].style.opacity="0"; x.getElementsByTagName('img')[0].style.transform = "scale(0,0)"; x.

我需要替换此CSS代码:

transform:scale(0,0);
transform-origin: top left;
用javascript代码,但我不知道怎么做

我在找这样的东西:

.style.opacity="0";
谢谢


我有这样的想法:

x.getElementsByTagName('img')[0].style.opacity="0";
x.getElementsByTagName('img')[0].style.transform = "scale(0,0)";
x.getElementsByTagName('img')[0].style.transformOrigin = "0 0";

1号没问题,2号和3号都不行。(Chrome,IE)

这应该适合您:

document.getElementById("your_elements_id").style.transform = 'scale(0,0)';
document.getElementById("your_elements_id").style.transformOrigin = '0 0';