Javascript 后续JSONP请求给出状态404,尽管GET状态为200
因此,我能够向yelpapi发出第一个JSONP请求,以便为我返回业务数据,但是我发出的任何后续请求都会导致对失败的回调,并记录404的状态代码。然而,当我在Chrome开发工具中打开网络选项卡时,我看到所有后续的GET请求都具有状态200,并且我确实看到了有效的响应数据。当调用失败回调时,这怎么可能呢?我怎样才能解决这个问题?我希望能够多次接收数据 下面讨论的代码基于对另一个问题的回答,不同之处在于注释正下方的语句Javascript 后续JSONP请求给出状态404,尽管GET状态为200,javascript,angularjs,asynchronous,jsonp,yelp,Javascript,Angularjs,Asynchronous,Jsonp,Yelp,因此,我能够向yelpapi发出第一个JSONP请求,以便为我返回业务数据,但是我发出的任何后续请求都会导致对失败的回调,并记录404的状态代码。然而,当我在Chrome开发工具中打开网络选项卡时,我看到所有后续的GET请求都具有状态200,并且我确实看到了有效的响应数据。当调用失败回调时,这怎么可能呢?我怎样才能解决这个问题?我希望能够多次接收数据 下面讨论的代码基于对另一个问题的回答,不同之处在于注释正下方的语句 <!DOCTYPE html> <html> <
<!DOCTYPE html>
<html>
<head>
<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.4.5/angular.min.js"></script>
<script src="oauth-signature.js"></script>
</head>
<body ng-app="plunker">
<div ng-controller="MainCtrl">
<p><date-input name="info.name" message="info.message"></date-input></p>
<ul>
<li data-ng-repeat="business in businesses">
{{business.name}}
</li>
</ul>
</div>
<script>
function randomString(length, chars) {
var result = '';
for (var i = length; i > 0; --i) result += chars[Math.round(Math.random() * (chars.length - 1))];
return result;
}
var app = angular.module('plunker', []);
app.controller('MainCtrl', ['$scope', 'MyYelpAPI', function($scope, MyYelpAPI) {
$scope.businesses = [];
// first time for the callback gets executed
MyYelpAPI.retrieveYelp('', function(data) {
console.log('callback1');
console.log('data');
$scope.businesses = data.businesses;
});
// the second time for the callback doesn't get executed
MyYelpAPI.retrieveYelp('', function(data) {
console.log('callback2');
$scope.businesses = data.businesses;
});
}]).factory("MyYelpAPI", function($http) {
return {
"retrieveYelp": function(name, callback) {
var method = 'GET';
var url = 'http://api.yelp.com/v2/search';
var params = {
callback: 'angular.callbacks._0',
location: 'San+Francisco',
oauth_consumer_key: '',
oauth_token: '',
oauth_signature_method: "HMAC-SHA1",
oauth_timestamp: new Date().getTime(),
oauth_nonce: randomString(32, '0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ'),
term: 'food'
};
var consumerSecret = '',
var tokenSecret = '',
var signature = oauthSignature.generate(method, url, params, consumerSecret, tokenSecret, { encodeSignature: false});
params['oauth_signature'] = signature;
$http.jsonp(url, {params: params})
.success(callback)
// second time fails
// data -> undefined; status -> 404
.error(function(data, status) {
console.log(data, status); // why is this happening?
});
}
}
});
</script>
</body>
</html>
-
{{business.name}
函数随机字符串(长度、字符){
var结果=“”;
对于(var i=length;i>0;--i)result+=chars[Math.round(Math.random()*(chars.length-1));
返回结果;
}
var app=angular.module('plunker',[]);
app.controller('MainCtrl',['$scope','MyYelpAPI',函数($scope,MyYelpAPI){
$scope.businesss=[];
//第一次执行回调
MyYelpap.retrieveYelp(“”,函数(数据){
console.log('callback1');
console.log(“数据”);
$scope.business=data.business;
});
//第二次回调没有执行
MyYelpap.retrieveYelp(“”,函数(数据){
console.log('callback2');
$scope.business=data.business;
});
}]).factory(“MyYelpAPI”,函数($http){
返回{
“retrieveYelp”:函数(名称、回调){
var方法='GET';
var url='1〕http://api.yelp.com/v2/search';
变量参数={
回调:'angular.callbacks.\u 0',
地点:“旧金山”,
oauth_消费者_密钥:“”,
oauth_令牌:“”,
oauth_签名_方法:“HMAC-SHA1”,
oauth_时间戳:新日期().getTime(),
oauth_nonce:randomString(32,'0123456789abcdefghijklmnopqrstuvwxyzabcdefghijklmnopqrstuvxyz'),
术语:“食物”
};
var consumerSecret='',
var tokenSecret='',
var signature=oauthSignature.generate(方法、url、参数、ConsumerCret、tokenSecret、{encodeSignature:false});
参数['oauth_签名']=签名;
$http.jsonp(url,{params:params})
.成功(回拨)
//第二次失败
//数据->未定义;状态->404
.错误(功能(数据、状态){
console.log(数据、状态);//为什么会发生这种情况?
});
}
}
});
您应该这样做:
$http.jsonp("api.yelp.com/v2/search?callback=JSON_CALLBACK", yourParams)
.success(function() {
//success callback
})
.error(function(){
//error callback
}) ;
我想你需要这样做$http.jsonp(“,params).success(function(){//success}).error(function(){//failure});将回调查询参数添加到url中就成功了。谢谢!