Javascript 如何从字符串中提取与禁止字数组中包含的字相匹配的字（并删除任何剩余的空白）？

如果给定一组禁止使用的单词，如何从字符串中提取某些单词

以Woody Allen的以下引用为例：

Love is the answer, 
but while you are waiting for the answer 
sex raises some pretty good questions

这是要从字符串中提取的单词数组：

var forbidden = new Array("is", "the", "but", "you", 
"are", "for", "the", "some", "pretty");

如何从字符串中提取任何单词，删除任何剩余的空白，从而得到以下结果：

Love answer, while waiting answer sex raises good questions

var quote=“爱是答案，但当你等待答案时，性会提出一些很好的问题”；
var probled=新数组（“is”、“the”、“but”、“you”、“are”、“for”、“the”、“some”、“pretty”）；
var isprobled={}；
var i；
对于（i=0；i<0.length；i++）{
isForbidden[i]]=true；
}
var words=quote.split（“”）；
var-sanitaryWords=[]；
对于（i=0；i

var quote=“爱是答案，但当你在等待答案时，性会提出一些很好的问题”；
var probled=新数组（“is”、“the”、“but”、“you”、“are”、“for”、“the”、“some”、“pretty”）；
var isprobled={}；
var i；
对于（i=0；i<0.length；i++）{
isForbidden[i]]=true；
}
var words=quote.split（“”）；
var-sanitaryWords=[]；
对于（i=0；i

试试看：

试试看：

 var quote = "Love is the answer, but while you are waiting for the answer sex raises some pretty good questions";
 var forbidden = new Array("is", "the", "but", "you", "are", "for", "the", "some", "pretty");

 var isForbidden = {};
 var i;

 for (i = 0; i < forbidden.length; i++) {
     isForbidden[forbidden[i]] = true;
 }

 var words = quote.split(" ");
 var sanitaryWords = [];

 for (i = 0; i < words.length; i++) {
     if (!isForbidden[words[i]]) {
          sanitaryWords.push(words[i]);
     }
 }

 alert(sanitaryWords.join(" "));

var quote = "Love is the answer,\nbut while you are waiting for the answer\nsex raises some pretty good questions";

var forbidden = ["is", "the", "but", "you", "are", "for", "the", "some", "pretty"];

var reg = RegExp('\\b(' + forbidden.join('|') + ')\\b\\s?', 'g');

alert(quote.replace(reg, ''));