Javascript 如何使用ajax codeigniter显示所选框

Javascript 如何使用ajax codeigniter显示所选框,javascript,jquery,ajax,codeigniter,Javascript,Jquery,Ajax,Codeigniter,我想编辑所选框,但在我有“编辑”按钮的情况下不显示它 这是我对javascript的看法: <script type="text/javascript"> function edit(id) { $('#form-edit').remove(); $.ajax({ type: 'POST', data: '', url: '<?php echo site_url("pangkat/edit")?>/' + id,

我想编辑所选框,但在我有“编辑”按钮的情况下不显示它

这是我对javascript的看法:

<script type="text/javascript">
  function edit(id) {
    $('#form-edit').remove();

    $.ajax({
      type: 'POST',
      data: '',
      url: '<?php echo site_url("pangkat/edit")?>/' + id,
      success: function(data) {
        obj = JSON.parse(data);
        var html = '' +
          '<form id="form-edit">' +
            '<div class="form-group">' +
              '<label class="control-label labelnya"><i class="ion ion-home"></i>Golongan:</label>' +
              '<select class="persons" name="id_golongan" style="width: 100%" data-placeholder="Pilih Golongan">' +
                '<option></option>' +
                <?php foreach($golongan as $val) {
                  if ($val['ID_GOLONGAN'] == $id_golongan)
                    echo '<option value="'.$val['ID_GOLONGAN'].'" selected>'.$val['GOLONGAN'].'</option>';
                  else
                    echo '<option value="'.$val['ID_GOLONGAN'].'">'.$val['GOLONGAN'].'</option>';
                }?>
              '</select>' +
            '</div>' +
          '</form>';
      }
    });
  }
</script>`

你的要求不清楚。。。解释..我想用comboboxFormatted代码博客显示数据库中的数据值,固定英语。
public function edit($id = NULL)
{
  // $data['golongan'] = $this->M_golongan->get();
  $data = $this->M_pangkat->get($id);
  echo json_encode(array(
    'id_pangkat'    =>$data['ID_KENAIKAN_PANGKAT'],
    'id_pegawai'    =>$data['ID_PEGAWAI'],
    'id_golongan'   =>$data['ID_GOLONGAN'],
    'sk_pangkat'    =>$data['SK_PANGKAT'],
    'tgl_mulai'     =>date('d-m-Y ',strtotime($data['TGL_MULAI'])),
    'tgl_terhitung' =>date('d-m-Y ',strtotime($data['TGL_TERHITUNG']))
  ));
}