Javascript 在等待async.map()完成后,如何返回推送数组?
最终结果将存储在下面的位置数组中Javascript 在等待async.map()完成后,如何返回推送数组?,javascript,promise,async-await,axios,Javascript,Promise,Async Await,Axios,最终结果将存储在下面的位置数组中 const locations = [] 我创建了一个异步函数,它接受一个location参数,locationSearch将使用该参数向googleplaces发出GET请求 const locationSearch = await ( axios.get(`https://maps.googleapis.com/maps/api/place/textsearch/json?query=${location}`, {json: true})
const locations = []
我创建了一个异步函数,它接受一个location参数,locationSearch将使用该参数向googleplaces发出GET请求
const locationSearch = await (
axios.get(`https://maps.googleapis.com/maps/api/place/textsearch/json?query=${location}`, {json: true})
.then(response => {
if(response.data.results.length < 1) throw new Error('Unable to find location.')
return response.data.results
}).catch(error => {
return error
})
)
但是,我不确定应该在哪里返回位置,因为locationDetails仅用于将结果映射到位置。已解决的承诺返回如下:
return Promise.all(locationSearch, locationDetails)
我希望这个问题不会让人觉得很傻。此外,任何关于所写代码错误的反馈或指点都将不胜感激 对于async/await,您不需要像.then和.catch这样使用promise API,它是使用promise结构的替代方法。它应该更像这样:
async function getLocationData (location) {
try {
const { data } = axios.get(
`https://maps.googleapis.com/maps/api/place/textsearch/json?query=${location}`,
{ json: true }
)
if (data.results) {
const locationDetails = await Promise.all(
data.results.map(({ place_id }) =>
// for each of these, catch any errors and return null so you know you got nothing
// but it won't kill the entire batch of requests
axios.get(
`https://maps.googleapis.com/maps/api/place/details/json?placeid=${id}`,
{ json: true }
).catch(() => null)
)
)
return locationDetails.reduce((arr, details) => {
// only add the data if it exists
if (Array.isArray(details.result) && details.result.length) {
const {
name,
geometry,
types,
photos,
rating,
user_ratings_total,
opening_hours,
icon,
formatted_address,
formatted_phone_number,
price_level,
reviews
} = details
return [
...arr,
{
latitude: geometry.location.lat,
longitude: geometry.location.lng,
types,
reviews,
photos,
rating,
user_ratings_total,
opening_hours,
icon,
name,
location: formatted_address,
formatted_phone_number,
price_level
}
]
}
// otherwise it's an errored result (null) or no match
// so return the accumulated array (essentially a filter)
return arr
}, [])
} else {
throw new Error('Unable to find location')
}
} catch (err) {
return err
}
}
这里需要注意的主要事情是,一旦任何请求失败,所有请求都将停止。因此,您可以向Promise.all映射中的每个axios调用添加.catch,以防止整个批拒绝。然后,您将得到一个与位置结果数量匹配的数组,现在您将得到失败的结果,因为它们将为null,或者您希望为失败的请求返回的任何内容
此外,在处理错误时保持一致也是一个好主意。要么一直扔,要么一直回来。解决这个问题的方法非常清晰明了,感谢您指出不同的方法!很高兴我能帮忙!
async function getLocationData (location) {
try {
const { data } = axios.get(
`https://maps.googleapis.com/maps/api/place/textsearch/json?query=${location}`,
{ json: true }
)
if (data.results) {
const locationDetails = await Promise.all(
data.results.map(({ place_id }) =>
// for each of these, catch any errors and return null so you know you got nothing
// but it won't kill the entire batch of requests
axios.get(
`https://maps.googleapis.com/maps/api/place/details/json?placeid=${id}`,
{ json: true }
).catch(() => null)
)
)
return locationDetails.reduce((arr, details) => {
// only add the data if it exists
if (Array.isArray(details.result) && details.result.length) {
const {
name,
geometry,
types,
photos,
rating,
user_ratings_total,
opening_hours,
icon,
formatted_address,
formatted_phone_number,
price_level,
reviews
} = details
return [
...arr,
{
latitude: geometry.location.lat,
longitude: geometry.location.lng,
types,
reviews,
photos,
rating,
user_ratings_total,
opening_hours,
icon,
name,
location: formatted_address,
formatted_phone_number,
price_level
}
]
}
// otherwise it's an errored result (null) or no match
// so return the accumulated array (essentially a filter)
return arr
}, [])
} else {
throw new Error('Unable to find location')
}
} catch (err) {
return err
}
}