Javascript 指向我的另一个网页的链接无效
我试图使用PHP的Twitter API，并创建了一个部分，用户可以在其中了解建议关注的人 这是我的文件getSuggestionSlug.php的源代码：Javascript 指向我的另一个网页的链接无效,javascript,php,jquery,html,css,Javascript,Php,Jquery,Html,Css,我试图使用PHP的Twitter API，并创建了一个部分，用户可以在其中了解建议关注的人 这是我的文件getSuggestionSlug.php的源代码： <?php include "methods.php"; oauthVerify(); if(isset($_GET["slug"]) && !empty($_GET["slug"])) { $return = (array) getSuggestionSlug($_GET["slug"]); } else
<?php
include "methods.php";
oauthVerify();
if(isset($_GET["slug"]) && !empty($_GET["slug"]))
{
$return = (array) getSuggestionSlug($_GET["slug"]);
}
else
{
header("Location: getSuggestion.php");
}
?>
<!DOCTYPE html>
<html lang="en">
<head>
<title>Twitter Analytics</title>
<meta charset="utf-8">
<meta name="viewport" content="width=device-width, initial-scale=1">
<link rel="stylesheet" href="http://maxcdn.bootstrapcdn.com/bootstrap/3.3.5/css/bootstrap.min.css">
<link rel="stylesheet" href="http://bootswatch.com/paper/bootstrap.min.css">
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.3/jquery.min.js"></script>
<script src="http://maxcdn.bootstrapcdn.com/bootstrap/3.3.5/js/bootstrap.min.js"></script>
<style>
.showcase
{
}
.showcase a
{
text-decoration: none !important;
}
.showcase:hover
{
background-color: #ededed;
box-shadow: 0 0 20px #ddd;
border-radius: 5px;
}
</style>
</head>
<body>
<nav class="navbar navbar-inverse">
<div class="container-fluid">
<div class="navbar-header">
<button type="button" class="navbar-toggle collapsed" data-toggle="collapse" data-target="#bs-example-navbar-collapse-2">
<span class="sr-only">Toggle navigation</span>
<span class="icon-bar"></span>
<span class="icon-bar"></span>
<span class="icon-bar"></span>
</button>
<a class="navbar-brand" href="index.php">Twitter Analyzer</a>
</div>
<div class="collapse navbar-collapse" id="bs-example-navbar-collapse-2">
<ul class="nav navbar-nav">
<li><a href="sentimentAnalysis.php">Sentiment Analyzer<span class="sr-only">(current)</span></a></li>
<li><a href="keywordLitics.php">Keyword Analytics</a></li>
<li class="dropdown active">
<a href="#" class="dropdown-toggle" data-toggle="dropdown" role="button" aria-expanded="false">More <span class="caret"></span></a>
<ul class="dropdown-menu" role="menu">
<li><a href="makeFriend.php">Make Friends</a> </li>
<li class="active"><a href="getSuggestion.php">Get suggestions whom to make Friends</a></li>
<li class="disabled"><a href="#">Coming Soon...</a></li>
<li><a href="logout.php">Log Out</a></li>
</ul>
</li>
</ul>
</div>
</div>
</nav>
<?php
$i = 0;
foreach($return["users"] as $user)
{
if($i >= 12)
{
break;
}
echo "<div class='showcase col-md-3' id='{$user->screen_name}' data-name=\"{$user->name}\" style='margin-left: 100px; margin-top: 5%; height: 150px; text-align: center; vertical-align: middle; font-size: large; cursor: pointer; padding: 1%;' onmouseover='showControls( \"{$user->name}\", \"{$user->screen_name}\" );'>" . $user->name . "</div>";
$i = $i + 1;
}
?>
<script src="script.js"></script>
<script>
$(".showcase").on("mouseleave", function(){$(".showcase").attr("style", "margin-left: 100px; margin-top: 5%; height: 150px; text-align: center; vertical-align: middle; font-size: large; cursor: pointer; padding: 1%;"); $("button").remove();});
</script>
</body>
</html>
推特分析
玻璃陈列柜
{
}
.展示
{
文字装饰：无！重要；
}
.展示：悬停
{
背景色：#ededed；
盒影：0 0 20px#ddd；
边界半径：5px；
}
切换导航
-
这和如下事实有关：当您在按钮上滑动鼠标时，showControls函数被多次调用。每次你这样做，它就会破坏并重新创建按钮
举个例子，试试这个。它仅在第一次创建控件。在这种情况下，它工作（无论如何一次）
var first=true；
var showControls=函数（名称、屏幕名称）{
如果（第一）{
第一个=假；
console.log（名称+“”+屏幕名称）；
$（“#”+屏幕名称）.attr（“样式”，“左侧边距：100px；顶部边距：5%；高度：150px；字体大小：大；光标：指针；填充：1%；”；
$（“#”+屏幕名称）.html（名称+”
）
}
};
也许一个解决方案是保留已存在控件的记录，然后仅在控件尚未存在时创建它们。将“我的按钮”转换为输入也无济于事。页面中呈现了什么？检查element@epascarello
var showControls = function(name, screen_name){
console.log(name + " " + screen_name);
$("#" + screen_name).attr("style", "margin-left: 100px; margin-top: 5%; height: 150px; font-size: large; cursor: pointer; padding: 1%;");
$("#" + screen_name).html(name + "<br /><br /><a href='userShow.php?screen_name=" + screen_name + "'><button class='btn btn-primary'>Get Details</button></a> <a href='makeFriend.php?screen_name=" + screen_name + "'><button class='btn btn-primary'>Make Friend</button></a>")
};
var first = true;
var showControls = function(name, screen_name){
if(first) {
first = false;
console.log(name + " " + screen_name);
$("#" + screen_name).attr("style", "margin-left: 100px; margin-top: 5%; height: 150px; font-size: large; cursor: pointer; padding: 1%;");
$("#" + screen_name).html(name + "<br /><br /><a href='userShow.php?screen_name=" + screen_name + "'><button class='btn btn-primary'>Get Details</button></a> <a href='makeFriend.php?screen_name=" + screen_name + "'><button class='btn btn-primary'>Make Friend</button></a>")
}
};