Javascript 如何按两个字段(包括日期)对数组排序
我有一个对象数组,我想先按日期排序,然后按数值排序Javascript 如何按两个字段(包括日期)对数组排序,javascript,sorting,Javascript,Sorting,我有一个对象数组,我想先按日期排序,然后按数值排序 let arr = [ {date: 2018-06-19 12:05:43.232Z, value: 3}, {date: 2018-06-20 12:05:43.232Z, value: 4}, {date: 2018-06-18 12:05:43.232Z, value: 2}, {date: 2018-06-20 12:05:43.232Z, value: 4}, {date: 2018-06-19 1
let arr = [
{date: 2018-06-19 12:05:43.232Z, value: 3},
{date: 2018-06-20 12:05:43.232Z, value: 4},
{date: 2018-06-18 12:05:43.232Z, value: 2},
{date: 2018-06-20 12:05:43.232Z, value: 4},
{date: 2018-06-19 12:05:43.232Z, value: 5},
{date: 2018-06-18 12:05:43.232Z, value: 5},
{date: 2018-06-20 12:05:43.232Z, value: 5},
{date: 2018-06-19 12:05:43.232Z, value: 4},
]
我想按日期和值对每个索引进行排序,结果如下:
let arr = [
{date: 2018-06-18 12:05:43.232Z, value: 2},
{date: 2018-06-18 12:05:43.232Z, value: 5},
{date: 2018-06-19 12:05:43.232Z, value: 3},
{date: 2018-06-19 12:05:43.232Z, value: 4},
{date: 2018-06-19 12:05:43.232Z, value: 5},
{date: 2018-06-20 12:05:43.232Z, value: 3},
{date: 2018-06-20 12:05:43.232Z, value: 4},
{date: 2018-06-20 12:05:43.232Z, value: 5},
]
如何操作?您可以使用Array.sort和
|
const res=arr.sort((a,b)=>Date.parse(a.Date)-Date.parse(b.Date)| a.value-b.value);
控制台日志(res)代码>
设arr=[{
日期:“2018-06-19 12:05:43.232Z”,
价值:3
},
{
日期:“2018-06-20 12:05:43.232Z”,
价值:4
},
{
日期:“2018-06-18 12:05:43.232Z”,
价值:2
},
{
日期:“2018-06-20 12:05:43.232Z”,
价值:4
},
{
日期:“2018-06-19 12:05:43.232Z”,
价值:5
},
{
日期:“2018-06-18 12:05:43.232Z”,
价值:5
},
{
日期:“2018-06-20 12:05:43.232Z”,
价值:5
},
{
日期:“2018-06-19 12:05:43.232Z”,
价值:4
},
]
您可以将Array.sort与|
const res=arr.sort((a,b)=>Date.parse(a.Date)-Date.parse(b.Date)| a.value-b.value);
控制台日志(res)代码>
设arr=[{
日期:“2018-06-19 12:05:43.232Z”,
价值:3
},
{
日期:“2018-06-20 12:05:43.232Z”,
价值:4
},
{
日期:“2018-06-18 12:05:43.232Z”,
价值:2
},
{
日期:“2018-06-20 12:05:43.232Z”,
价值:4
},
{
日期:“2018-06-19 12:05:43.232Z”,
价值:5
},
{
日期:“2018-06-18 12:05:43.232Z”,
价值:5
},
{
日期:“2018-06-20 12:05:43.232Z”,
价值:5
},
{
日期:“2018-06-19 12:05:43.232Z”,
价值:4
},
]
您可以使用lodash库来完成。如果你查看功能文档,你会发现,这正是你所需要的
let arr = [
{"date": "2018-06-19 12:05:43.232Z", "value": 3},
{"date": "2018-06-20 12:05:43.232Z", "value": 4},
{"date": "2018-06-18 12:05:43.232Z", "value": 2},
{"date": "2018-06-20 12:05:43.232Z", "value": 4},
{"date": "2018-06-19 12:05:43.232Z", "value": 5},
{"date": "2018-06-18 12:05:43.232Z", "value": 5},
{"date": "2018-06-20 12:05:43.232Z", "value": 5},
{"date": "2018-06-19 12:05:43.232Z", "value": 4}
]
在阵列上应用\u orderBy
,如下所示:
_.orderBy(arr, ['date', 'value'], ['asc', 'asc']);
你会得到你想要的结果
检查以下示例:
让arr=[
{“日期”:“2018-06-19 12:05:43.232Z”,“值”:3},
{“日期”:“2018-06-20 12:05:43.232Z”,“值”:4},
{“日期”:“2018-06-18 12:05:43.232Z”,“值”:2},
{“日期”:“2018-06-20 12:05:43.232Z”,“值”:4},
{“日期”:“2018-06-19 12:05:43.232Z”,“值”:5},
{“日期”:“2018-06-18 12:05:43.232Z”,“值”:5},
{“日期”:“2018-06-20 12:05:43.232Z”,“值”:5},
{“日期”:“2018-06-19 12:05:43.232Z”,“值”:4}
]
console.log(u.orderBy(arr,['date','value',['asc','asc']))
您可以使用lodash库来完成。如果你查看功能文档,你会发现,这正是你所需要的
let arr = [
{"date": "2018-06-19 12:05:43.232Z", "value": 3},
{"date": "2018-06-20 12:05:43.232Z", "value": 4},
{"date": "2018-06-18 12:05:43.232Z", "value": 2},
{"date": "2018-06-20 12:05:43.232Z", "value": 4},
{"date": "2018-06-19 12:05:43.232Z", "value": 5},
{"date": "2018-06-18 12:05:43.232Z", "value": 5},
{"date": "2018-06-20 12:05:43.232Z", "value": 5},
{"date": "2018-06-19 12:05:43.232Z", "value": 4}
]
在阵列上应用\u orderBy
,如下所示:
_.orderBy(arr, ['date', 'value'], ['asc', 'asc']);
你会得到你想要的结果
检查以下示例:
让arr=[
{“日期”:“2018-06-19 12:05:43.232Z”,“值”:3},
{“日期”:“2018-06-20 12:05:43.232Z”,“值”:4},
{“日期”:“2018-06-18 12:05:43.232Z”,“值”:2},
{“日期”:“2018-06-20 12:05:43.232Z”,“值”:4},
{“日期”:“2018-06-19 12:05:43.232Z”,“值”:5},
{“日期”:“2018-06-18 12:05:43.232Z”,“值”:5},
{“日期”:“2018-06-20 12:05:43.232Z”,“值”:5},
{“日期”:“2018-06-19 12:05:43.232Z”,“值”:4}
]
console.log(u.orderBy(arr,['date','value',['asc','asc']))
通过谷歌搜索js数组排序
。不是同一个问题。我希望按两个字段进行排序。这是我的问题。我可以按日期或值排序,但我希望在回调中同时按日期和值排序,您可以比较9000多个字段。不是同一个问题。我希望按两个字段进行排序。这是我的问题。我可以按日期或值排序,但我希望在回调中按两者进行排序,您可以比较9000多个字段。非常感谢您做了这么多完美的工作!欢迎@obiwankenoobithank@obiwankenoobithank你做了这么多完美的工作!欢迎你@obiwankenoobi