Javascript 如何在地图中的圆上设置不同的颜色
我在Javascript 如何在地图中的圆上设置不同的颜色,javascript,angular,typescript,amcharts,Javascript,Angular,Typescript,Amcharts,我在amchartsplugin中实现了一个地图,并在我有服务器的地方画了一个圆圈 我想根据业务需求,根据可用性在服务器上显示不同的颜色绿色、黄色和红色。我已经在首选位置实现了圆圈,并且我只能指定一种颜色 这是我的密码 public ServerMap() { this.mapChart = am4core.create("chartdiv", am4maps.MapChart); this.mapChart .geodata = am4geodata_wor
amcharts
plugin
中实现了一个地图,并在我有服务器的地方画了一个圆圈
我想根据业务需求,根据可用性在服务器上显示不同的颜色绿色
、黄色
和红色
。我已经在首选位置实现了圆圈,并且我只能指定一种颜色
这是我的密码
public ServerMap()
{
this.mapChart = am4core.create("chartdiv", am4maps.MapChart);
this.mapChart .geodata = am4geodata_worldLow;
//Set projection
this.mapChart .projection = new am4maps.projections.Miller();
//Create map polygon series
this.polygonSeries = this.mapChart .series.push(new am4maps.MapPolygonSeries());
this.polygonSeries.exclude = ["AQ"];
this.polygonSeries.useGeodata = true;
this.polygonSeries.nonScalingStroke = true;
this.polygonSeries.calculateVisualCenter = true;
let imageSeries = this.mapChart .series.push(new am4maps.MapImageSeries());
imageSeries.dataFields.value = "value";
var place = imageSeries.mapImages.template;
place.nonScaling = true;
place.propertyFields.latitude = "latitude";
place.propertyFields.longitude = "longitude";
imageSeries.data=
[
{
"latitude": 17.3850,
"longitude": 78.4867,
"name": "Miam",
"value": 123,
},
{
"latitude":49.619446,
"longitude": -128.695623,
"name": "Washingto DC",
"value": 123,
},
{
"latitude": 41.8278767,
"longitude": -87.9986114,
"name": "Chicago",
"value": 123,
}
]
//Here creating circle
var circle = place.createChild(am4core.Circle);
circle.radius = 12;
circle.fill = am4core.color("#e33");
circle.strokeWidth = 1;
circle.fillOpacity = 0.7;
circle.propertyFields.fill = "color";
circle.tooltipText = "{name}: [bold]{value}[/]";
imageSeries.heatRules.push({
"target": circle,
"property": "radius",
"min": 6,
"max": 15,
"dataField": "value",
})
}
如何根据条件在圆上设置单个颜色
这是我的输出屏幕
您已经定义了“circle.propertyFields.fill=“color”;”
在数据中包含“颜色”属性应该是可行的
imageSeries.data=
[
{
"latitude": 17.3850,
"longitude": 78.4867,
"name": "Miam",
"value": 123,
"color": 'red' // or rgb() or Hexa
},
{
"latitude":49.619446,
"longitude": -128.695623,
"name": "Washingto DC",
"value": 123,
"color": 'blue'
},
非常感谢。是否可以根据
if-else
条件更改颜色?