Javascript React Redux with Redux observable异步操作完成后,使用路由器导航到不同的页面
我正在使用,这是我的登录史诗:Javascript React Redux with Redux observable异步操作完成后,使用路由器导航到不同的页面,javascript,reactjs,redux,react-router,rxjs,Javascript,Reactjs,Redux,React Router,Rxjs,我正在使用,这是我的登录史诗: const login = ( action$ ) => { return action$.ofType(SessionActions.LOGIN_USER) .flatMap(( {payload} ) => { return sessionService.login(payload) .do(payload => { sessionService.setSessi
const login = ( action$ ) => {
return action$.ofType(SessionActions.LOGIN_USER)
.flatMap(( {payload} ) => {
return sessionService.login(payload)
.do(payload => {
sessionService.setSession(payload));
// Here I want to redirect the user back to his last location
}).map(result => ({
type: SessionActions.LOGIN_SUCCESS,
payload: result
}));
});
}
但是我如何在登录操作成功后将用户重定向到不同的页面
redux的方法是什么?我对react/redux完全陌生,但我面临着与您相同的问题,因此我创建了一个带有登录页面的小应用程序
// On your Login.JS you could implement the component lifecycle
componentWillReceiveProps(nextProps) {
if (nextProps.isAuthenticated){
this.context.router.push({pathname:'/'});
}
}
因此,当您的“操作”向“减速器”发送类型:LOGIN\u SUCCESS时,您将更改相应的状态;当您的组件“接收道具”时,您将检查并重定向。我希望这个小示例对您有所帮助。如果使用with,您可以在epics中执行任何重定向:
import { ajax } from 'rxjs/observable/dom/ajax';
import { push } from 'react-router-redux';
import NProgress from 'nprogress';
import 'rxjs/add/operator/map';
import 'rxjs/add/operator/mergeMap';
export default function login(action$) {
return action$.ofType('LOGIN_USER')
.do(() => NProgress.start())
.mergeMap(payload => (
// Call your login service here, please note that it must be an observable to continue in your epic chain.
Observable.fromPromise(sessionService.setSession(payload))
// This is the redirect you're looking for, it's now became an action thanks to react-router-redux :)
.mapTo(push({ url: '/' }))
.do(() => NProgress.done())
));
}
我甚至为奖励积分添加了一个进度指标:)它是在的帮助下构建的,我并没有真正注意到mapTo的功能。非常感谢你。