在javascript函数中使用return时出现问题

我正在使用Esri ArcMap API 我做了一个函数，可以查询图层并返回结果， 我想让这个函数返回结果，以便在制作小部件时使用它

function queryLayer(filterType,value){

    var x 

    schoolLayer.definitionExpression = filterType+" = '" + value + "'";

    const queryParams = schoolLayer.createQuery();
    queryParams.where =  filterType +" = '" + value + "'";
    queryParams.outFields = [filterType]
    schoolLayer.queryFeatures(queryParams).then(function (results) {

        x = results.features
    });
   return x
}

---

这是一个承诺，承诺是异步的

schoolLayer.queryFeatures(queryParams).then(function (results) {
    x = results.features
});

您可以在resolve函数中返回结果：

function queryLayer(filterType,value){
    schoolLayer.definitionExpression = filterType+" = '" + value + "'";
    const queryParams = schoolLayer.createQuery();
    queryParams.where =  filterType +" = '" + value + "'";
    queryParams.outFields = [filterType]
    schoolLayer.queryFeatures(queryParams).then(function (results) {
        return results.features;
    });
}

---

如果这不起作用，您可以退还全部承诺：

function queryLayer(filterType,value){
    schoolLayer.definitionExpression = filterType+" = '" + value + "'";
    const queryParams = schoolLayer.createQuery();
    queryParams.where =  filterType +" = '" + value + "'";
    queryParams.outFields = [filterType]
    return schoolLayer.queryFeatures(queryParams);
}

然后像这样使用它：

queryLayer(filterType,value).then(funtction(response){
    // do whatever you want to do with your Response ...
}

---

不，第一个不行。