Javascript 从复杂JSON迭代到表中
我正在努力使用JavaScript中的可选链接将JSON对象映射到Javascript 从复杂JSON迭代到表中,javascript,json,reactjs,react-bootstrap,optional-chaining,Javascript,Json,Reactjs,React Bootstrap,Optional Chaining,我正在努力使用JavaScript中的可选链接将JSON对象映射到React中的表。这是有效载荷: { "originating request": { "id":1, "name":"ali", "markets": [ { "name": "Winner
React
中的表。这是有效载荷:
{
"originating request": {
"id":1,
"name":"ali",
"markets": [
{
"name": "Winner",
"selections": [
{
"name": "Manchester United",
"probability": "1.0"
},
{
"name": "Tottenham Hotspur",
"probability": "0.0"
},
{
"name": "Arsenal",
"probability": "0.0"
}
]
},
{
"name": "Finish Last",
"selections": [
{
"name": "Manchester United",
"probability": "0.0"
},
{
"name": "Tottenham Hotspur",
"probability": "0.0"
},
{
"name": "Arsenal",
"probability": "1.0"
}
]
}
]
}
}
以前,markets
数组中只有一个对象,即Winner
market。这是我针对该场景的解决方案,在该方案中,我会立即筛选出获胜者
,并遍历该表:
return (
<div>
<Table striped bordered hover size="sm" responsive>
<thead>
<tr className="same-col-widths">
<th>Team Name</th>
<th>Winner</th>
</thead>
<tbody>
{simResult?.markets?.length
? simResult.markets
.find(t => t.name === "Winner")
.selections.map((selection, index) => (
<tr key={index}>
<td>{selection.name}</td>
<td>{selection.probability}</td>
</tr>
))
: null}
</tbody>
</Table>
</div>
)
在一列中列出团队名称,在相关列中列出与正确市场对应的所有概率。执行此操作的最佳方法是什么?因此,首先要使用reduce
重新格式化输入数据,以收集每个团队(表中的每一行)的所有数据,以便在创建表时更轻松地映射这些数据。如果将来输入格式发生变化,将此逻辑从表创建中分离也会使您更有弹性
const reformattedData = data["originating request"].markets.reduce(
(accumulator, market) =>
market.selections.map(({ name, probability }, index) => ({
...accumulator[index],
"Team name": name,
[market.name]: probability,
})),
[],
);
这将以更便于表格的格式提供:
[
{ "Team name": "Manchester United", "Winner": "1.0", "Finish Last": "0.0" },
{ "Team name": "Tottenham Hotspur", "Winner": "0.0", "Finish Last": "0.0" },
{ "Team name": "Arsenal", "Winner": "0.0", "Finish Last": "1.0" },
]
然后,您可以使用这个新对象的键来映射并获取表头列表,然后映射每个对象的值以创建行
<table>
<thead>
<tr>
{Object.keys(reformattedData[0]).map((header, index) => (
<th key={index}>{header}</th>
))}
</tr>
</thead>
<tbody>
{reformattedData.map((teamData, index) => (
<tr key={index}>
{Object.values(teamData).map((cellInfo, index) => (
<td key={index}>{cellInfo}</td>
))}
</tr>
))}
</tbody>
</table>
{Object.keys(重新格式化数据[0]).map((头,索引)=>(
{header}
))}
{重新格式化数据.map((团队数据,索引)=>(
{Object.values(teamData.map)((cellInfo,index)=>(
{cellInfo}
))}
))}
看到它在这个中工作了吗?你在数据json中有“赢家”和“最后完成”的概率,你打算如何将其转换为表中的“赢家”和“前两名完成”呢?啊,输入错误。它是为了表示我将添加的未来对象。我已将“前两名完成”更正为“最后完成”
<table>
<thead>
<tr>
{Object.keys(reformattedData[0]).map((header, index) => (
<th key={index}>{header}</th>
))}
</tr>
</thead>
<tbody>
{reformattedData.map((teamData, index) => (
<tr key={index}>
{Object.values(teamData).map((cellInfo, index) => (
<td key={index}>{cellInfo}</td>
))}
</tr>
))}
</tbody>
</table>