Javascript 动态Google应用程序脚本数组构造失败

从本质上讲，我正在查看先前创建的二维数组，并希望输出与另一个二维数组中的特定情况匹配的每个值

function FruitsToEat() {
  var fruits = [
    ["Name",      "TastesGood?", "ShouldEat?"],
    ["Apple",     true,          true],
    ["Orange",    false,         true],
    ["Grapes',    true,          true],
    ["Forbidden", true,          false]
  ];
  var EatThese = [];
  var i = 0;
  var rows = 0;
  var columns = 0;

  for (i = 0; i < fruits.length; i++) {        //Check the entire Array
    if (fruits[i][2] == true) {                //If the "ShouldEat?" column = true
      if (column != 2) {                       //Once column reaches 2, make a new row
        EatThese[row][column] = fruits[i][0];  //Set the cell to the fruit name
        column++;                              //Move to the right in the array
      } else {
        row++;                                 //Move down one in the array
        column = 0;                            //Move back to the left of the array
        EatThese[row][column] = fruits[i][0];  //Set the cell to the fruit name
        column++;                              //Move to the right in the array
      }
    }
  }

  return EatThese;
}

当我期待的时候

Apple Orange
Grapes

在各自的单元格中，以单张形式显示

所以我自己在打字时解决了这个问题。我将把这个留在这里，因为我在任何地方都找不到帮助

如果有人能告诉我，我仍然想知道为什么我最初的想法不起作用

function FruitsToEat() {
  var fruits = [
    ["Name",      "TastesGood?", "ShouldEat?"],
    ["Apple",     true,          true],
    ["Orange",    false,         true],
    ["Grapes',    true,          true],
    ["Forbidden", true,          false]
  ];
  var EatThese = [];                          //This is our main array and will be what we return.
  var EatTheseTemp = [];                      //This is our temporary array. It will store each row of the main array until it is filled.
  var i = 0;
  var rows = 0;
  var columns = 0;

  for (i = 0; i < fruits.length; i++) {        //Check the entire Array
    if (fruits[i][2] == true) {                //If the "ShouldEat?" column = true
      if (column != 2) {                       //Our fill detection
        EatTheseTemp[column] = fruits[i][0];   //Set the cell to the fruit name
        column++;                              //Move to the right in the temporary array
      } else {
        EatThese[row] = EatTheseTemp;          //Start constructing the main array
        row++;                                 //Prepare for the next fill
        column = 0;                            //Move back to the left of the temporary array
        EatTheseTemp = [];                     //Reset our temporary array
        EatTheseTemp[column] = fruits[i][0];   //Set the cell to the fruit name
        column++;                              //Move to the right in the temporary array
      }
    }
  }

  EatThese[row] = EatTheseTemp;

  return EatThese;
}

函数FruitsToEat（）{
风险值=[
[“姓名”，“味道好吗？”，“应该吗？”]，
[“苹果”，真的，真的]，
[“橙色”，假，真]，
[“葡萄”，真的，真的]，
[“禁止”，对，错]
];
var eatthes=[]；//这是我们的主数组，将返回它。
var EATTESTEMP=[]；//这是我们的临时数组。它将存储主数组的每一行，直到填充为止。
var i=0；
var行=0；
var列=0；
对于（i=0；i

---

基本上，我创建了两个数组。每次初始if语句返回true时，一个数组都会向其中添加片段。一旦嵌入的if语句显示此数组已填充，则将完整的行添加到主数组，然后擦除其他变量以重新开始。在for循环之外，您需要添加最后一行和两个d维度数组已完成。

您的初始代码不起作用，因为您试图为

eatthes[0][0]

赋值。您已将

eatthes

定义为数组，但未定义数组的元素…

eatthes[0]

将是

未定义的

，直到您为其分配了某些内容。在这种情况下，请将其设置为数组…

eatthes[0]=[]；

，然后您可以继续分配

eatthes[0][0]

。可能存在重复的

function FruitsToEat() {
  var fruits = [
    ["Name",      "TastesGood?", "ShouldEat?"],
    ["Apple",     true,          true],
    ["Orange",    false,         true],
    ["Grapes',    true,          true],
    ["Forbidden", true,          false]
  ];
  var EatThese = [];                          //This is our main array and will be what we return.
  var EatTheseTemp = [];                      //This is our temporary array. It will store each row of the main array until it is filled.
  var i = 0;
  var rows = 0;
  var columns = 0;

  for (i = 0; i < fruits.length; i++) {        //Check the entire Array
    if (fruits[i][2] == true) {                //If the "ShouldEat?" column = true
      if (column != 2) {                       //Our fill detection
        EatTheseTemp[column] = fruits[i][0];   //Set the cell to the fruit name
        column++;                              //Move to the right in the temporary array
      } else {
        EatThese[row] = EatTheseTemp;          //Start constructing the main array
        row++;                                 //Prepare for the next fill
        column = 0;                            //Move back to the left of the temporary array
        EatTheseTemp = [];                     //Reset our temporary array
        EatTheseTemp[column] = fruits[i][0];   //Set the cell to the fruit name
        column++;                              //Move to the right in the temporary array
      }
    }
  }

  EatThese[row] = EatTheseTemp;

  return EatThese;
}