Javascript 使用Greasemonkey帮助隐藏基于文本内容的DIV标记

我正在寻找一种编写Greasemonkey脚本的方法，该脚本将采用以下代码片段，并仅显示由

组成的代码块。下面是一个使用的脚本。困难的部分是选择

请注意

@jared farrish来自《潜入油脂城》杂志：var allDivs，thisDiv；allDivs=document.evaluate（“//div[@class='sponsoredlink']”，document，null，XPathResult.UNORDERED\u NODE\u SNAPSHOT\u TYPE，null）；对于（var i=0；i<div class="A">
    <div class="B">
        <a href="/link1">
        <img class="imgClass" src="http://link.com/img.img" title="imgTitle"/>
        </a>
    </div>
    <div class="C">
        <span class="sc1">passtest</span>
        <br/>
        <em class="ec1">City1, State1</em>
    </div>
</div>
<div class="A">
    <div class="B">
        <a href="/link1">
        <img class="imgClass" src="http://link.com/img.img" title="imgTitle"/>
        </a>
    </div>
    <div class="C">
        <span class="sc1">failtest </span>
        <br/>
        <em class="ec1">City1, State1 </em>
    </div>
</div>
<div class="A">
    <div class="B">
        <a href="/link1">
        <img class="imgClass" src="http://link.com/img.img" title="imgTitle"/>
        </a>
    </div>
    <div class="C">
        <span class="sc1">passtest </span>
        <br/>
        <em class="ec1">City2, State2 </em>
    </div>
</div>

var allDivs, thisDiv;
allDivs = document.evaluate("//div[@class='sponsoredlink']", document, null, XPathResult.UNORDERED_NODE_SNAPSHOT_TYPE, null);
for (var i = 0; i < allDivs.snapshotLength; i++) {
    thisDiv = allDivs.snapshotItem(i); 
    // do something with thisDiv 
}

// ==UserScript==
// @name     Show State1 passes only.
// @include  http://YOUR_SITE/YOUR_PATH/*
// @require  http://ajax.googleapis.com/ajax/libs/jquery/1.6.2/jquery.min.js
// ==/UserScript==

$("div.A")  .hide ()
            .has ("span.sc1:contains('passtest')")
            .has ("em.ec1:contains('State1')")
            .show ();