Javascript Firestore复合查询

我需要使用

在工作日包含“午后”：true或“晚间”：true或晨：true；

示例insert monday和saturday返回字段userAvailability中包含“午后”：true或“晚间”：true或morning:true的所有用户

而且不能。。。试试这个

---

usersfirestore.where（'Monday'，'array contains'，true）不幸的是，在Firestore中无法执行

或
查询。您需要运行多个单独的查询并将结果组合在一起。
不幸的是，在Firestore中无法执行
或
查询。您将需要运行多个单独的查询并将结果组合在一起

  Object {
    "countryCode": "US",
    "createdAt": 1615080719516,
    "email": "alew14@gmail.com",
    "emailVerified": false,
    "firstName": "alejandro pereira",
    "gender": "Male",
    "id": "MrAPuFOFdqdlgMofaH2UomIFAU42",
    "lastLoginAt": 1615080719516,
    "lastName": "no last name",
    "photoURL": null,
    "userAuthenticated": true,
    "userAvailability": Object {
      "friday": Object {
        "afternoon": false,
        "evening": false,
        "morning": true,
      },
      "monday": Object {
        "afternoon": false,
        "evening": false,
        "morning": true,
      },
      "saturday": Object {
        "afternoon": false,
        "evening": false,
        "morning": true,
      },
      "sunday": Object {
        "afternoon": true,
        "evening": false,
        "morning": true,
      },
      "thursday": Object {
        "afternoon": false,
        "evening": false,
        "morning": true,
      },
      "tuesday": Object {
        "afternoon": false,
        "evening": false,
        "morning": true,
      },
      "wednesday": Object {
        "afternoon": false,
        "evening": false,
        "morning": true,
      },
    },
  }