如何动态合并两个JavaScript对象的属性？
我需要能够在运行时合并两个（非常简单的）JavaScript对象。例如，我想：如何动态合并两个JavaScript对象的属性？,javascript,javascript-objects,Javascript,Javascript Objects,我需要能够在运行时合并两个（非常简单的）JavaScript对象。例如，我想： var obj1 = { food: 'pizza', car: 'ford' } var obj2 = { animal: 'dog' } obj1.merge(obj2); //obj1 now has three properties: food, car, and animal 有没有人有这样的脚本，或者知道一种内置的方式来实现这一点？我不需要递归，也不需要合并函数，只需要平面对象上的方法。ECMASc
var obj1 = { food: 'pizza', car: 'ford' }
var obj2 = { animal: 'dog' }
obj1.merge(obj2);
//obj1 now has three properties: food, car, and animal
有没有人有这样的脚本，或者知道一种内置的方式来实现这一点？我不需要递归，也不需要合并函数，只需要平面对象上的方法。ECMAScript 2018标准方法
/* For the case in question, you would do: */
Object.assign(obj1, obj2);
/** There's no limit to the number of objects you can merge.
* All objects get merged into the first object.
* Only the object in the first argument is mutated and returned.
* Later properties overwrite earlier properties with the same name. */
const allRules = Object.assign({}, obj1, obj2, obj3, etc);
o = mergeRecursive({a:'a'}, 1, true, null, undefined, [1,2,3], 'bc', new String('de'));
// o = {0:'d', 1:'e', 2:3, a:'a'}
mergedobj1obj2obj2obj1/** There's no limit to the number of objects you can merge.
* Later properties overwrite earlier properties with the same name. */
const allRules = {...obj1, ...obj2, ...obj3};
/* For the case in question, you would do: */
Object.assign(obj1, obj2);
/** There's no limit to the number of objects you can merge.
* All objects get merged into the first object.
* Only the object in the first argument is mutated and returned.
* Later properties overwrite earlier properties with the same name. */
const allRules = Object.assign({}, obj1, obj2, obj3, etc);
ES5及更早版本的方法
for (var attrname in obj2) { obj1[attrname] = obj2[attrname]; }
obj2obj1obj1/** There's no limit to the number of objects you can merge.
* Later properties overwrite earlier properties with the same name. */
const allRules = {...obj1, ...obj2, ...obj3};
hasOwnProperty/**
* Overwrites obj1's values with obj2's and adds obj2's if non existent in obj1
* @param obj1
* @param obj2
* @returns obj3 a new object based on obj1 and obj2
*/
function merge_options(obj1,obj2){
var obj3 = {};
for (var attrname in obj1) { obj3[attrname] = obj1[attrname]; }
for (var attrname in obj2) { obj3[attrname] = obj2[attrname]; }
return obj3;
}
Object.extend = function(destination,source) {
for (var property in source)
destination[property] = source[property];
return destination;
}
obj1.extend（obj2）// Merge options object into settings object
var settings = { validate: false, limit: 5, name: "foo" };
var options = { validate: true, name: "bar" };
jQuery.extend(settings, options);
// Now the content of settings object is the following:
// { validate: true, limit: 5, name: "bar" }
设置的现有对象
如果要在不修改任一参数的情况下创建新对象，请使用以下命令：
var defaults = { validate: false, limit: 5, name: "foo" };
var options = { validate: true, name: "bar" };
/* Merge defaults and options, without modifying defaults */
var settings = $.extend({}, defaults, options);
// The content of settings variable is now the following:
// {validate: true, limit: 5, name: "bar"}
// The 'defaults' and 'options' variables remained the same.
我在谷歌上搜索了合并对象属性的代码，结果出现在这里。然而，由于没有任何递归合并的代码，我自己编写了它。（顺便说一句，也许jqueryextend是递归的？）
（现在代码不使用对象。prototype
：）
代码
一个例子
生成类似于o3的对象
o3 = { a : 10,
b : 2,
c : {
ca : 10,
cb : 20,
cc : {
cca : 101,
ccb : 202 } } };
指定前，应修改给定的解决方案，以检查中的source.hasOwnProperty（property）
。在循环中。否则，您将复制整个原型链的属性，这是很少需要的…在中，有：
对于不太复杂的对象，可以使用：
请注意，在本例中，“}{”不能出现在字符串中！执行此操作的最佳方法是使用Object.defineProperty添加不可枚举的适当属性
通过这种方式，您仍然可以迭代对象属性，而不必使用新创建的“extend”（扩展），如果您使用Object.prototype.extend创建属性，就会得到这个“extend”
希望这有助于：
Object.defineProperty(Object.prototype, "extend", {
enumerable: false,
value: function(from) {
var props = Object.getOwnPropertyNames(from);
var dest = this;
props.forEach(function(name) {
if (name in dest) {
var destination = Object.getOwnPropertyDescriptor(from, name);
Object.defineProperty(dest, name, destination);
}
});
return this;
}
});
Object.defineProperty（Object.prototype，“extend”{
可枚举：false，
值：函数（从）{
var props=Object.getOwnPropertyNames（来自）；
var dest=此；
props.forEach（函数（名称）{
如果（目的地名称）{
var destination=Object.getOwnPropertyDescriptor（from，name）；
Object.defineProperty（目的地、名称、目的地）；
}
});
归还这个；
}
});
一旦你有工作，你可以做：
var obj = {
name: 'stack',
finish: 'overflow'
}
var replacement = {
name: 'stock'
};
obj.extend(replacement);
var obj={
名称：'堆栈'，
完成：“溢出”
}
var替换={
名称：“股票”
};
对象扩展（替换）；
我刚刚在这里写了一篇博文：我扩展了David Coalier的方法：
- 增加了合并多个对象的可能性
- 支持深度对象
- 覆盖参数（如果最后一个参数是布尔值，则会检测到该参数）
如果override为false，则不会覆盖任何属性，但会添加新属性
用法：
对象合并（合并…[覆盖]）
这是我的密码：
Object.defineProperty(Object.prototype, "merge", {
enumerable: false,
value: function () {
var override = true,
dest = this,
len = arguments.length,
props, merge, i, from;
if (typeof(arguments[arguments.length - 1]) === "boolean") {
override = arguments[arguments.length - 1];
len = arguments.length - 1;
}
for (i = 0; i < len; i++) {
from = arguments[i];
if (from != null) {
Object.getOwnPropertyNames(from).forEach(function (name) {
var descriptor;
// nesting
if ((typeof(dest[name]) === "object" || typeof(dest[name]) === "undefined")
&& typeof(from[name]) === "object") {
// ensure proper types (Array rsp Object)
if (typeof(dest[name]) === "undefined") {
dest[name] = Array.isArray(from[name]) ? [] : {};
}
if (override) {
if (!Array.isArray(dest[name]) && Array.isArray(from[name])) {
dest[name] = [];
}
else if (Array.isArray(dest[name]) && !Array.isArray(from[name])) {
dest[name] = {};
}
}
dest[name].merge(from[name], override);
}
// flat properties
else if ((name in dest && override) || !(name in dest)) {
descriptor = Object.getOwnPropertyDescriptor(from, name);
if (descriptor.configurable) {
Object.defineProperty(dest, name, descriptor);
}
}
});
}
}
return this;
}
});
我的equals方法可以在这里找到：在4中，它可以按如下方式完成：
var mergedObject = Ext.Object.merge(object1, object2)
// Or shorter:
var mergedObject2 = Ext.merge(object1, object2)
请参见。我今天需要合并对象，这个问题（和答案）对我帮助很大。我尝试了一些答案，但没有一个符合我的需要，因此我将一些答案合并，自己添加了一些内容，并提出了一个新的合并功能。如下所示：
var merge=function（）{
var obj={}，
i=0，
il=arguments.length，
钥匙
对于（；i
一些示例用法：
var t1={
关键1:1，
键2：“测试”，
键3:[5,2,76,21]
};
变量t2={
关键1：{
ik1：“你好”，
ik2：“世界”，
ik3:3
}
};
变量t3={
关键2:3，
关键3：{
t1:1，
t2:2，
t3：{
a1:1，
a2:3，
a4:[21、3、42，“建筑署”]
}
}
};
console.log（合并（t1，t2））；
console.log（合并（t1，t3））；
console.log（合并（t2，t3））；
日志（合并（t1、t2、t3））；
log（merge（{}，t1，{key1:1}））；
基于和，这是一个扩展版本。该函数接受任意数量的参数。它可用于设置节点上的属性并制作值的深度副本。但是，第一个参数通过引用给出
要检测DOM节点，使用isDOMNode（）函数（请参见StackOverflow问题）
它在11、Firefox 6和Google Chrome 16中进行了测试
代码
合并数组和对象。请注意，未定义可用于在左侧数组/对象中保存值
o = mergeRecursive({a:'a'}, [1,2,3], [undefined, null, [30,31]], {a:undefined, b:'b'});
// o = {0:1, 1:null, 2:[30,31], a:'a', b:'b'}
任何不属于JavaScript对象的参数（包括null）都将被忽略。除第一个参数外，DOM节点也将被丢弃。请注意，像new String（）一样创建的字符串实际上是对象
o = mergeRecursive({a:'a'}, 1, true, null, undefined, [1,2,3], 'bc', new String('de'));
// o = {0:'d', 1:'e', 2:3, a:'a'}
如果要将两个对象合并为一个新对象（而不影响这两个对象中的任何一个），请提供{}作为第一个参数
var a={}, b={b:'abc'}, c={c:'cde'}, o;
o = mergeRecursive(a, b, c);
// o===a is true, o===b is false, o===c is false
编辑（由ReaperSoon提供）：
也可以合并数组
function mergeRecursive(obj1, obj2) {
if (Array.isArray(obj2)) { return obj1.concat(obj2); }
for (var p in obj2) {
try {
// Property in destination object set; update its value.
if ( obj2[p].constructor==Object ) {
obj1[p] = mergeRecursive(obj1[p], obj2[p]);
} else if (Array.isArray(obj2[p])) {
obj1[p] = obj1[p].concat(obj2[p]);
} else {
obj1[p] = obj2[p];
}
} catch(e) {
// Property in destination object not set; create it and set its value.
obj1[p] = obj2[p];
}
}
return obj1;
}
请注意，s在一行程序中执行此操作：
_.extend({name : 'moe'}, {age : 50});
=> {name : 'moe', age : 50}
如果有人正在使用：o = mergeRecursive({a:'a'}, [1,2,3], [undefined, null, [30,31]], {a:undefined, b:'b'});
// o = {0:1, 1:null, 2:[30,31], a:'a', b:'b'}
o = mergeRecursive({a:'a'}, 1, true, null, undefined, [1,2,3], 'bc', new String('de'));
// o = {0:'d', 1:'e', 2:3, a:'a'}
var a={}, b={b:'abc'}, c={c:'cde'}, o;
o = mergeRecursive(a, b, c);
// o===a is true, o===b is false, o===c is false
function mergeRecursive(obj1, obj2) {
if (Array.isArray(obj2)) { return obj1.concat(obj2); }
for (var p in obj2) {
try {
// Property in destination object set; update its value.
if ( obj2[p].constructor==Object ) {
obj1[p] = mergeRecursive(obj1[p], obj2[p]);
} else if (Array.isArray(obj2[p])) {
obj1[p] = obj1[p].concat(obj2[p]);
} else {
obj1[p] = obj2[p];
}
} catch(e) {
// Property in destination object not set; create it and set its value.
obj1[p] = obj2[p];
}
}
return obj1;
}
_.extend({name : 'moe'}, {age : 50});
=> {name : 'moe', age : 50}
goog.require('goog.object');
var a = {'a': 1, 'b': 2};
var b = {'b': 3, 'c': 4};
goog.object.extend(a, b);
// Now object a == {'a': 1, 'b': 3, 'c': 4};
var a = [1, 2];
var b = [3, 4];
goog.array.extend(a, b); // Extends array 'a'
goog.array.concat(a, b); // Returns concatenation of array 'a' and 'b'
var realMerge = function (to, from) {
for (n in from) {
if (typeof to[n] != 'object') {
to[n] = from[n];
} else if (typeof from[n] == 'object') {
to[n] = realMerge(to[n], from[n]);
}
}
return to;
};
var merged = realMerge(obj1, obj2);
/*
Recursively merge properties and return new object
obj1 <- obj2 [ <- ... ]
*/
function merge () {
var dst = {}
,src
,p
,args = [].splice.call(arguments, 0)
;
while (args.length > 0) {
src = args.splice(0, 1)[0];
if (toString.call(src) == '[object Object]') {
for (p in src) {
if (src.hasOwnProperty(p)) {
if (toString.call(src[p]) == '[object Object]') {
dst[p] = merge(dst[p] || {}, src[p]);
} else {
dst[p] = src[p];
}
}
}
}
}
return dst;
}
a = {
"p1": "p1a",
"p2": [
"a",
"b",
"c"
],
"p3": true,
"p5": null,
"p6": {
"p61": "p61a",
"p62": "p62a",
"p63": [
"aa",
"bb",
"cc"
],
"p64": {
"p641": "p641a"
}
}
};
b = {
"p1": "p1b",
"p2": [
"d",
"e",
"f"
],
"p3": false,
"p4": true,
"p6": {
"p61": "p61b",
"p64": {
"p642": "p642b"
}
}
};
c = {
"p1": "p1c",
"p3": null,
"p6": {
"p62": "p62c",
"p64": {
"p643": "p641c"
}
}
};
d = merge(a, b, c);
/*
d = {
"p1": "p1c",
"p2": [
"d",
"e",
"f"
],
"p3": null,
"p5": null,
"p6": {
"p61": "p61b",
"p62": "p62c",
"p63": [
"aa",
"bb",
"cc"
],
"p64": {
"p641": "p641a",
"p642": "p642b",
"p643": "p641c"
}
},
"p4": true
};
*/
// Merge the 'options' object into the 'settings' object
var settings = {validate: false, limit: 5, name: "foo"};
var options = {validate: true, name: "bar"};
angular.extend(settings, options);
var arrayOfObjects = [ {a:1}, {b:2, c:3}, {d:4} ];
_(arrayOfObjects).reduce(function(memo, o) { return _(memo).extend(o); });
Object {a: 1, b: 2, c: 3, d: 4}
Object.assign(obj1, obj2);
var obj1 = { val1: false, limit: 5, name: "foo" };
var obj2 = { val2: true, name: "bar" };
jQuery.extend(obj1, obj2);
var o1 = { a: 1 };
var o2 = { b: 2 };
var o3 = { c: 3 };
var obj = Object.assign(o1, o2, o3);
console.log(obj); // { a: 1, b: 2, c: 3 }
console.log(o1); // { a: 1, b: 2, c: 3 }, target object itself is changed.
var clone = Object.assign({}, obj);
if (!Object.assign) {
Object.defineProperty(Object, 'assign', {
enumerable: false,
configurable: true,
writable: true,
value: function(target) {
'use strict';
if (target === undefined || target === null) {
throw new TypeError('Cannot convert first argument to object');
}
var to = Object(target);
for (var i = 1; i < arguments.length; i++) {
var nextSource = arguments[i];
if (nextSource === undefined || nextSource === null) {
continue;
}
nextSource = Object(nextSource);
var keysArray = Object.keys(nextSource);
for (var nextIndex = 0, len = keysArray.length; nextIndex < len; nextIndex++) {
var nextKey = keysArray[nextIndex];
var desc = Object.getOwnPropertyDescriptor(nextSource, nextKey);
if (desc !== undefined && desc.enumerable) {
to[nextKey] = nextSource[nextKey];
}
}
}
return to;
}
});
}
_.defaultsDeep({ 'user': { 'name': 'barney' } }, { 'user': { 'name': 'fred', 'age': 36 } });
// → { 'user': { 'name': 'barney', 'age': 36 } }
var obj1 = { food: 'pizza', car: 'ford' }
var obj2 = { animal: 'dog' }
// result
result: {food: "pizza", car: "ford", animal: "dog"}
// Merge obj1 & obj2 to result
var result1 = $.extend( {}, obj1, obj2 );
// Merge obj1 & obj2 to result
var result2 = _.merge( {}, obj1, obj2 );
// Merge obj1 & obj2 to result
var result3 = _.extend( {}, obj1, obj2 );
// Merge obj1 & obj2 to result
var result4 = Object.assign( {}, obj1, obj2 );
obj1: { animal: 'dog' }
obj2: { food: 'pizza', car: 'ford' }
result1: {food: "pizza", car: "ford", animal: "dog"}
result2: {food: "pizza", car: "ford", animal: "dog"}
result3: {food: "pizza", car: "ford", animal: "dog"}
result4: {food: "pizza", car: "ford", animal: "dog"}