Javascript react子组件正在覆盖redux状态
当我的父级渲染它覆盖子级消息时,我为每个父级组件获得了2条相同的消息。请帮帮我。下面是我的父组件。 例如,我的父母有4个项目Javascript react子组件正在覆盖redux状态,javascript,reactjs,redux,react-redux,Javascript,Reactjs,Redux,React Redux,当我的父级渲染它覆盖子级消息时,我为每个父级组件获得了2条相同的消息。请帮帮我。下面是我的父组件。 例如,我的父母有4个项目 { project1: { message1: 'hello this message for project 1',message2: 'messsage 2 for project 1'}, project2: { message1: 'hello this message for project 2',message2: 'messsage 2 for pr
{
project1: { message1: 'hello this message for project 1',message2: 'messsage 2 for project 1'},
project2: { message1: 'hello this message for project 2',message2: 'messsage 2 for project 2'}
};
但我得到的是产出
project1: { message1: 'hello this message for project 2',message2: 'messsage 2 for project 2'};
project2: { message1: 'hello this message for project 2',message2: 'messsage 2 for project 2'};
我希望项目1显示自己的消息,项目2显示自己的消息,但redux正在覆盖我的状态
import React, { Component } from 'react';
import PropTypes from 'prop-types';
import { connect } from 'react-redux';
import { projectsFetchData } from '../actions/projects';
import MessageList from './MessageList';
class Projects extends Component {
componentDidMount() {
this.props.fetchData('https://api.proworkflow.net/projects?apikey=9ZVM-873H-3JPK-C55Q-PWFE7MN-TR86485');
}
render() {
if (this.props.hasErrored) {
return <p>Sorry! There was an error loading the items</p>;
}
if (this.props.isLoading) {
return <p>Loading…</p>;
}
return (
<div className="container">
<div className="panel panel-primary">
<div className="panel-heading clearfix">
<div className="header-logo pull-left" />
<div className="pull-right heading">
<span className="glyphicon glyphicon-envelope" aria-hidden="true"></span>
Project Messages
</div>
</div>
<div className="panel-body secondry">
{this.props.projects.map((item) => (
<div className="media" key={item.id}>
<div className="media-body">
<h4 className="media-heading"><i>{item.companyname}</i></h4>
<p><i>{item.title}</i></p>
<MessageList projectId={item.id} />
</div>
</div>
))}
</div>
</div>
</div>
);
}
}
Projects.propTypes = {
fetchData: PropTypes.func.isRequired,
projects: PropTypes.array.isRequired,
hasErrored: PropTypes.bool.isRequired,
isLoading: PropTypes.bool.isRequired
};
const mapStateToProps = (state) => {
return {
projects: state.projects,
hasErrored: state.projectsHasErrored,
isLoading: state.projectsIsLoading
};
};
const mapDispatchToProps = (dispatch) => {
return {
fetchData: (url) => dispatch(projectsFetchData(url))
};
};
export default connect(mapStateToProps, mapDispatchToProps)(Projects);
这是因为两个项目共享相同的redux状态 我不确定添加名称空间是否会对您有所帮助,因为您的项目列表可能有任意数量的项目。然而,我认为它可能会给你一些解决共享状态问题的提示
您可以添加projectMessages减缩器,而不是使用消息减缩器 儿童减速机
export function messagesHasErrored(state = false, action) {
switch (action.type) {
case 'MESSAGES_HAS_ERRORED':
return action.hasErrored;
default:
return state;
}
}
export function messagesIsLoading(state = false, action) {
switch (action.type) {
case 'MESSAGES_IS_LOADING':
return action.isLoading;
default:
return state;
}
}
export function messages(state = [], action) {
switch (action.type) {
case 'MESSAGES_FETCH_DATA_SUCCESS':
return action.messages;
default:
return state;
}
}
export function projectMessages(state = {}, action) {
switch (action.type) {
case 'PROJECT_MESSAGES_FETCH_DATA_SUCCESS':
return Object.Assign({}, state, {action.payload.projectId: action.payload.messages});
default:
return state;
}
}
在行动上:
export function projectMessagesFetchDataSuccess(messages, projectId) {
return {
type: "PROJECT_MESSAGES_FETCH_DATA_SUCCESS",
payload: { projectId: projectId, messages: message }
};
}
In-MessageComponent:通过获取项目的消息
this.prop.projectMessages[this.props.projectId]
例如:
projectMessages = {"project1": ["m1", "m2", "m3"], "project2": ["m4", "m5", "m6"]};
如果您想获得project2的消息,可以这样做
var messagesOfProject2 = projectMessages["project2"];
设计中存在一些问题
项目
状态发生更改时,都会呈现该属性
MessageList
组件本身中,您使用的是statemessages:state.messages
状态发生变化时,将要求组件重新渲染。消息
因此,通过这种方式,消息组件被渲染两次
解决方案:
在父组件中,删除要传递的特性
代替
写
从projects:state.projects
语句中,projects
是state的一部分
因此,在子组件(MessageList
)中循环它
在子组件中,您的MapStateStorops
将
const mapStateToProps = (state) => {
return {
messages: state.messages,// remove it
hasErrored: state.messagesHasErrored,
isLoading: state.messagesIsLoading,
projects : state.projects //added in child component
};
};
从状态树中删除messages:state.messages
,作为MessageList
组件的唯一内部状态。您可以在内部存储它并循环它
在子组件中,在
componentDidMount() {
let projectId = null;
this.props.projects.map((item) =>{
projectId = item.id;
this.props.fetchData(`https://api.proworkflow.net/projects/${projectId}/messages?apikey=9ZVM-873H-3JPK-C55Q-PWFE7MN-TR86485`);
})
}
现在,只要父组件中的项目
状态发生更改,
您的子组件(MessageList)将使用更新的项目id数据重新呈现。但如何获取特定项目的消息。?请帮助我,但我如何才能得到特定项目的消息。?请帮帮我
componentDidMount() {
let projectId = null;
this.props.projects.map((item) =>{
projectId = item.id;
this.props.fetchData(`https://api.proworkflow.net/projects/${projectId}/messages?apikey=9ZVM-873H-3JPK-C55Q-PWFE7MN-TR86485`);
})
}