Javascript Node.js:读取URL中传递的参数
在rails中,我向服务器发出POST请求:Javascript Node.js:读取URL中传递的参数,javascript,node.js,coffeescript,Javascript,Node.js,Coffeescript,在rails中,我向服务器发出POST请求: response = Typhoeus::Request.post("http://url.localtunnel.com/request?from=ola&to=ole") result = JSON.parse(response.body) 在Node.js应用程序中,我想从和到: app.post '/request', (req,res) -> console.log "I have received a reques
response = Typhoeus::Request.post("http://url.localtunnel.com/request?from=ola&to=ole")
result = JSON.parse(response.body)
在Node.js应用程序中,我想从和到:
app.post '/request', (req,res) ->
console.log "I have received a request, sweet!!"
sys.log req.params.from
#sys.log "From: " + req.from + ", To: " + req.to + ", Id: " + req.id
我该怎么做
谢谢答案是:
Checks query string params (req.query), ex: ?id=12
大概是这样的:
var http = require('http'), url = require('url');
http.createServer(function(request, response) {
response.writeHead(200, {"Content-Type":"text/plain"});
var _url = url.parse(request.url, true);
response.write("Hello " + _url.query["from"] + "!\n"); // etc: _url.query["to"]...
response.close();
}).listen(8000);
url.parse
是一个关键点。。。或者您可以使用querystring.parse(urlString)
您可以在docs部分阅读更多内容。没错,Express中的
参数是从您定义的路由解析而来的,例如app.get('/user/:id',…
为您提供了一个req.param.id
。您需要req.query
。请注意,在这里它是get
还是POST
请求并不重要。