Javascript 如果两个字段相同,如何使用JSON COUNT-sum对值求和
这是我的JSON文件Javascript 如果两个字段相同,如何使用JSON COUNT-sum对值求和,javascript,php,mysql,json,Javascript,Php,Mysql,Json,这是我的JSON文件 {"result":[ {"beer":"23","store":"1","table":"1"}, {"beer":"12","store":"1","table":"1"}, {"beer":"5","store":"1","table":"2"}]} 如果store和table字段相同,我想计算beer的总和 结果应为2条记录: beer 35, store 1 table 1 beer 5, store 1 table 2 这是我使用的MYSQL查询: $sql
{"result":[
{"beer":"23","store":"1","table":"1"},
{"beer":"12","store":"1","table":"1"},
{"beer":"5","store":"1","table":"2"}]}
如果store和table字段相同,我想计算beer的总和
结果应为2条记录:
beer 35, store 1 table 1
beer 5, store 1 table 2
这是我使用的MYSQL查询:
$sql = "SELECT * FROM data ORDER BY beer DESC";
$res = mysql_query($sql);
$result = array();
while( $row = mysql_fetch_array($res) )
array_push($result, array('beer' => $row[1],
'store' => $row[2],
'table' => $row[3]));
echo json_encode(array("result" => $result));
希望您需要
分组方式
$sql = "
SELECT sum(beer) as beer, store, table
FROM data
GROUP BY store, table
ORDER BY beer DESC
";
要直接从sql执行此操作,请执行以下操作: $query=“选择总和(啤酒)作为啤酒、商店、表格 从数据 按存储、表格分组” 从json中求和:
$json_result = json_decode($json_var) ;
$result = array() ;
foreach($json_result->result as $key=>$value){
if(!isset($result[$value->store])){
$result[$value->store] = array() ;
$result[$value->store][$value->table] = $value->beer ;
}
else if(!isset($result[$value->store][$value->table])){
$result[$value->store][$value->table] = $value->beer ;
}
else{
$result[$value->store][$value->table] += $value->beer ;
}
}
$result will contain the json sum
请把你的标题改成小写,你的问题是什么?@rene:
JSON
按设计是大写的,sql关键字按惯例也是大写的。所以这很好。@zerkms我对此有不同的看法…@rene:即使你有-你保留了原始单词的大写字母。这意味着你的“不同”观点与我的完全一致-D