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Javascript 带有产品id的php echo不会同时显示在html文件中_Javascript_Php_Html - Fatal编程技术网

Javascript 带有产品id的php echo不会同时显示在html文件中

Javascript 带有产品id的php echo不会同时显示在html文件中,javascript,php,html,Javascript,Php,Html,我有两个php代码和两个不同的产品id。如果我选择代表2个id之一的块,然后选择代表剩余产品id的块,则此代码将仅显示最后选择的产品id 此代码用于将产品添加到购物车。因此,当a选择了id为product\u id\u subscribtion的产品,然后我选择了id为product\u id\u separate的产品时,它将只显示id为product\u id\u separate的产品 顺便说一句,我使用get方法来形成$\u COOKIE: <?php $getU

我有两个php代码和两个不同的
产品id
。如果我选择代表2个id之一的块,然后选择代表剩余产品id的块,则此代码将仅显示最后选择的
产品id

此代码用于将产品添加到购物车。因此,当a选择了id为
product\u id\u subscribtion
的产品,然后我选择了id为
product\u id\u separate
的产品时,它将只显示id为
product\u id\u separate
的产品

顺便说一句,我使用get方法来形成
$\u COOKIE

<?php    

    $getUsers = $dbh->prepare("SELECT * FROM productssubscription WHERE product_id = ?");
    $getUsers->execute(array($_COOKIE['product_id_subscribtion']));
    $users = $getUsers->fetchAll();

    foreach ($users as $user) {
        echo "<h1>" . $user['amount'] . " Panty's per maand"   . "</h1>";
        echo "<h1>" . "Prijs: " . $user['price'] . "</h1>";
  }
    ?>

还有这个

<?php    

    $getUsers = $dbh->prepare("SELECT * FROM productsseperate WHERE product_id = ?");
    $getUsers->execute(array($_COOKIE['product_id_seperate']));
    $users = $getUsers->fetchAll();

    foreach ($users as $user) {
        echo "<h1>" . $user['amount'] . " Panty's"   . "</h1>";
        echo "<h1>" . "Prijs: " . $user['price'] . "</h1>";
    }



    ?>