Javascript 用js-xlsx解析Excel工作表
我试图解析用户指定目录中的所有excel文件,但我使用的js xlsx库似乎需要手动导航Javascript 用js-xlsx解析Excel工作表,javascript,excel,parsing,Javascript,Excel,Parsing,我试图解析用户指定目录中的所有excel文件,但我使用的js xlsx库似乎需要手动导航 var url = "/test-files/test.xlsx"; <-------- Located in the project directory var oReq = new XMLHttpRequest(); oReq.open("GET", url, true); oReq.responseType = "arraybuffer"; oReq.onload = function(e)
var url = "/test-files/test.xlsx"; <-------- Located in the project directory
var oReq = new XMLHttpRequest();
oReq.open("GET", url, true);
oReq.responseType = "arraybuffer";
oReq.onload = function(e) {
var arraybuffer = oReq.response;
var data = new Uint8Array(arraybuffer);
var arr = new Array();
for (var i = 0; i != data.length; i++) arr[i] = String.fromCharCode(data[i]);
var bstr = arr.join("");
var workbook = XLSX.read(bstr, {
type: "binary"
});
}
oReq.send();
var url=“/test files/test.xlsx” 对于那些好奇的人,我想出了一个解决办法 要动态创建指向给定fileEntry对象的路径,必须首先将其转换为Blob:
fileEntryObject.file(function(file) {});
然后将其转换为window.URL,这样您的项目就可以访问所需文件的可读路径:
var newPath = window.URL.createObjectURL(file);
因此,即使您不知道如何从项目导航到文件,您也可以在函数中将其用作常规路径:
fileEntryObject.file(function(file) {
var newPath = window.URL.createObjectURL(file);
var oReq = new XMLHttpRequest();
oReq.open("GET", newPath, true);
oReq.responseType = "arraybuffer";
oReq.onError = function(e) {
console.log('Error in reading excel file');
};
oReq.onload = function(e) {
var arraybuffer = oReq.response;
var data = new Uint8Array(arraybuffer);
var arr = new Array();
for (var i = 0; i != data.length; ++i) arr[i] = String.fromCharCode(data[i]);
var bstr = arr.join("");
var workbook = XLSX.read(bstr, {
type: "binary"
});
var sheet_name = workbook.SheetNames[1];
var worksheet = workbook.Sheets[sheet_name];
self.parseReceive(worksheet, callback);
// self.parseReceive(worksheet);
};
oReq.send();
});
如果要缩短此代码,可以使用let bstr=new Uint8Array(oReq.response)在一行中获得一个二进制字符串。reduce((string,el)=>string+string.fromCharCode(el),“”)
您知道解析excel文件后数组的名称是什么或如何访问它吗?