Javascript 如何访问函数对象中的函数?
目前,我已将github中的代码添加到我的代码中:Javascript 如何访问函数对象中的函数?,javascript,function,object,Javascript,Function,Object,目前,我已将github中的代码添加到我的代码中: var ExcelFormulas = { PVIF: function(rate, nper) { return Math.pow(1 + rate, nper); }, FVIFA: function(rate, nper) { return rate == 0? nper: (this.PVIF(rate, nper) - 1) / rate; }, PMT
var ExcelFormulas = {
PVIF: function(rate, nper) {
return Math.pow(1 + rate, nper);
},
FVIFA: function(rate, nper) {
return rate == 0? nper: (this.PVIF(rate, nper) - 1) / rate;
},
PMT: function(rate, nper, pv, fv, type) {
if (!fv) fv = 0;
if (!type) type = 0;
if (rate == 0) return -(pv + fv)/nper;
var pvif = Math.pow(1 + rate, nper);
var pmt = rate / (pvif - 1) * -(pv * pvif + fv);
if (type == 1) {
pmt /= (1 + rate);
};
return pmt;
},
IPMT: function(pv, pmt, rate, per) {
var tmp = Math.pow(1 + rate, per);
return 0 - (pv * tmp * rate + pmt * (tmp - 1));
},
PPMT: function(rate, per, nper, pv, fv, type) {
if (per < 1 || (per >= nper + 1)) return null;
var pmt = this.PMT(rate, nper, pv, fv, type);
var ipmt = this.IPMT(pv, pmt, rate, per - 1);
return pmt - ipmt;
},
DaysBetween: function(date1, date2) {
var oneDay = 24*60*60*1000;
return Math.round(Math.abs((date1.getTime() - date2.getTime())/oneDay));
},
// Change Date and Flow to date and value fields you use
XNPV: function(rate, values) {
var xnpv = 0.0;
var firstDate = new Date(values[0].Date);
for (var key in values) {
var tmp = values[key];
var value = tmp.Flow;
var date = new Date(tmp.Date);
xnpv += value / Math.pow(1 + rate, this.DaysBetween(firstDate, date)/365);
};
return xnpv;
},
XIRR: function(values, guess) {
if (!guess) guess = 0.1;
var x1 = 0.0;
var x2 = guess;
var f1 = this.XNPV(x1, values);
var f2 = this.XNPV(x2, values);
for (var i = 0; i < 100; i++) {
if ((f1 * f2) < 0.0) break;
if (Math.abs(f1) < Math.abs(f2)) {
f1 = this.XNPV(x1 += 1.6 * (x1 - x2), values);
}
else {
f2 = this.XNPV(x2 += 1.6 * (x2 - x1), values);
}
};
if ((f1 * f2) > 0.0) return null;
var f = this.XNPV(x1, values);
if (f < 0.0) {
var rtb = x1;
var dx = x2 - x1;
}
else {
var rtb = x2;
var dx = x1 - x2;
};
for (var i = 0; i < 100; i++) {
dx *= 0.5;
var x_mid = rtb + dx;
var f_mid = this.XNPV(x_mid, values);
if (f_mid <= 0.0) rtb = x_mid;
if ((Math.abs(f_mid) < 1.0e-6) || (Math.abs(dx) < 1.0e-6)) return x_mid;
};
return null;
}
};
但是当我尝试用PPMT做类似的事情时,我得到了null。这就是我正在尝试的:
var values =
[
{rate:0.53, per: 1, nper : 12, pv:10000}
];
alert(ExcelFormulas.XIRR(values));
有人能帮我访问PPMT功能吗?提前谢谢你
旁注:只要有效,您可以输入任何值,我只需要一个示例您的PPMT函数在定义顶部有一个控制结构
PPMT: function(rate, per, nper, pv, fv, type) {
// will return null if condition is met
if (per < 1 || (per >= nper + 1)) return null;
var pmt = this.PMT(rate, nper, pv, fv, type);
var ipmt = this.IPMT(pv, pmt, rate, per - 1);
return pmt - ipmt;
},
您知道如何调用函数吗?函数被正确调用,因此这必须是关于该函数中的逻辑首先,您仍然在调用XIRR而不是PPMT。其次,PPMT似乎要求6!值,不是对象,不是数组-在您的值中,您只有4个缺少的类型-您应该这样调用它:alertExcelFormulas.PPMTrate、per、nper、pv、fv、type;-要么给出这些值:var rate=0.53,per=1,nper=12,pv=10000,fv=**你需要什么**,type=**你需要什么**;或者直接:alertExcelFormulas.PPMT0.53,1,12,10000,**您需要的任何fv**,**您需要的任何类型**;您不是在调用PPMT函数,而是在调用XIRR函数。在警报中,您应该有Excel公式。PPMT0.53,1,12,10000。你应该有两个更多的值在最后的fv和类型。谢谢大家!这些答案的组合帮助我找到了答案,这真的很有帮助。抱歉,响应时间太长,我的电脑有问题
PPMT: function(rate, per, nper, pv, fv, type) {
// will return null if condition is met
if (per < 1 || (per >= nper + 1)) return null;
var pmt = this.PMT(rate, nper, pv, fv, type);
var ipmt = this.IPMT(pv, pmt, rate, per - 1);
return pmt - ipmt;
},