Javascript 如何访问函数对象中的函数?

Javascript 如何访问函数对象中的函数?,javascript,function,object,Javascript,Function,Object,目前,我已将github中的代码添加到我的代码中: var ExcelFormulas = { PVIF: function(rate, nper) { return Math.pow(1 + rate, nper); }, FVIFA: function(rate, nper) { return rate == 0? nper: (this.PVIF(rate, nper) - 1) / rate; }, PMT

目前,我已将github中的代码添加到我的代码中:

var ExcelFormulas = {

    PVIF: function(rate, nper) {
        return Math.pow(1 + rate, nper);
    },

    FVIFA: function(rate, nper) {
        return rate == 0? nper: (this.PVIF(rate, nper) - 1) / rate;
    },  

    PMT: function(rate, nper, pv, fv, type) {
        if (!fv) fv = 0;
        if (!type) type = 0;

        if (rate == 0) return -(pv + fv)/nper;
        
        var pvif = Math.pow(1 + rate, nper);
        var pmt = rate / (pvif - 1) * -(pv * pvif + fv);

        if (type == 1) {
            pmt /= (1 + rate);
        };

        return pmt;
    },

    IPMT: function(pv, pmt, rate, per) {
        var tmp = Math.pow(1 + rate, per);
        return 0 - (pv * tmp * rate + pmt * (tmp - 1));
    },

    PPMT: function(rate, per, nper, pv, fv, type) {
        if (per < 1 || (per >= nper + 1)) return null;
        var pmt = this.PMT(rate, nper, pv, fv, type);
        var ipmt = this.IPMT(pv, pmt, rate, per - 1);
        return pmt - ipmt;
    },
    
    DaysBetween: function(date1, date2) {
        var oneDay = 24*60*60*1000;
        return Math.round(Math.abs((date1.getTime() - date2.getTime())/oneDay));
    },
    
    // Change Date and Flow to date and value fields you use
    XNPV: function(rate, values) {
        var xnpv = 0.0;
        var firstDate = new Date(values[0].Date);
        for (var key in values) {
            var tmp = values[key];
            var value = tmp.Flow;
            var date = new Date(tmp.Date);
            xnpv += value / Math.pow(1 + rate, this.DaysBetween(firstDate, date)/365);
        };
        return xnpv;
    },

    XIRR: function(values, guess) {
        if (!guess) guess = 0.1;
        
        var x1 = 0.0;
        var x2 = guess;
        var f1 = this.XNPV(x1, values);
        var f2 = this.XNPV(x2, values);
        
        for (var i = 0; i < 100; i++) {
            if ((f1 * f2) < 0.0) break;
            if (Math.abs(f1) < Math.abs(f2)) {
                f1 = this.XNPV(x1 += 1.6 * (x1 - x2), values);
            }
            else {
                f2 = this.XNPV(x2 += 1.6 * (x2 - x1), values);
            }
        };
        
        if ((f1 * f2) > 0.0) return null;
        
        var f = this.XNPV(x1, values);
        if (f < 0.0) {
            var rtb = x1;
            var dx = x2 - x1;
        }
        else {
            var rtb = x2;
            var dx = x1 - x2;
        };
        
        for (var i = 0; i < 100; i++) {
            dx *= 0.5;
            var x_mid = rtb + dx;
            var f_mid = this.XNPV(x_mid, values);
            if (f_mid <= 0.0) rtb = x_mid;
            if ((Math.abs(f_mid) < 1.0e-6) || (Math.abs(dx) < 1.0e-6)) return x_mid;
        };
        
        return null;
    }

};
但是当我尝试用PPMT做类似的事情时,我得到了null。这就是我正在尝试的:

var values =
[
{rate:0.53, per: 1, nper : 12, pv:10000}
];
alert(ExcelFormulas.XIRR(values));
有人能帮我访问PPMT功能吗?提前谢谢你

旁注:只要有效,您可以输入任何值,我只需要一个示例

您的PPMT函数在定义顶部有一个控制结构

    PPMT: function(rate, per, nper, pv, fv, type) {
        // will return null if condition is met
        if (per < 1 || (per >= nper + 1)) return null;
        var pmt = this.PMT(rate, nper, pv, fv, type);
        var ipmt = this.IPMT(pv, pmt, rate, per - 1);
        return pmt - ipmt;
    },

您知道如何调用函数吗?函数被正确调用,因此这必须是关于该函数中的逻辑首先,您仍然在调用XIRR而不是PPMT。其次,PPMT似乎要求6!值,不是对象,不是数组-在您的值中,您只有4个缺少的类型-您应该这样调用它:alertExcelFormulas.PPMTrate、per、nper、pv、fv、type;-要么给出这些值:var rate=0.53,per=1,nper=12,pv=10000,fv=**你需要什么**,type=**你需要什么**;或者直接:alertExcelFormulas.PPMT0.53,1,12,10000,**您需要的任何fv**,**您需要的任何类型**;您不是在调用PPMT函数,而是在调用XIRR函数。在警报中,您应该有Excel公式。PPMT0.53,1,12,10000。你应该有两个更多的值在最后的fv和类型。谢谢大家!这些答案的组合帮助我找到了答案,这真的很有帮助。抱歉,响应时间太长,我的电脑有问题
    PPMT: function(rate, per, nper, pv, fv, type) {
        // will return null if condition is met
        if (per < 1 || (per >= nper + 1)) return null;
        var pmt = this.PMT(rate, nper, pv, fv, type);
        var ipmt = this.IPMT(pv, pmt, rate, per - 1);
        return pmt - ipmt;
    },