Javascript 获取jquery变量中的Php字符串

我想在jquery变量中使用以下php字符串

{
'05-10-2018' : '<a href='http:www.google.com/' target='_blank'>Seeing dads differently</a>',
'05-10-2018' : '<a href='http:www.google.com/' target='_blank'>Extraordinary ordinary Britain</a>',
'05-10-2018' : '<a href='http:www.google.com/' target='_blank'> Roll up for the Social Science Market!</a>',
'05-10-2018' : '<a href='http:www.google.com/' target='_blank'>Why do we use it?</a>',
'05-10-2018' : '<a href='http:www.google.com/' target='_blank'>Extraordinary ordinary Britain</a>'
}

{
'05-10-2018' : '',
'05-10-2018' : '',
'05-10-2018' : '',
'05-10-2018' : '',
'05-10-2018' : ''
}

试试这段代码

<?php
    $phpstring = "{'05-10-2018' : '<a href='http:www.google.com/' target='_blank'>Seeing dads differently</a>','05-10-2018' : '<a href='http:www.google.com/' target='_blank'>Extraordinary ordinary Britain</a>','05-10-2018' : '<a href='http:www.google.com/' target='_blank'> Roll up for the Social Science Market!</a>',
    '05-10-2018' : '<a href='http:www.google.com/' target='_blank'>Why do we use it?</a>','05-10-2018' : '<a href='http:www.google.com/' target='_blank'>Extraordinary ordinary Britain</a>'}";
    $phpstring = json_encode($phpstring);

    echo "<script> var TestVar = $phpstring;</script>";
?>

---

您可以在jquery中使用php变量，如：

<script type="text/javascript">
    var php_string;
    php_string = "<?= $phpstring ?>";
</script>


var-php_字符串；
php_string=“”；
这个问题需要认真重写……这是php json字符串吗？我想要的是劳斯莱斯幻影。不是json，而是简单的phpstring@u_mulder，她说这是一个简单的php字符串，而不是json.var事件={'10-17-2018'：'“target=_blank>Eaque molestiae assumenda requisitibus alias dignessimos quod facere！”，'09-22-2018'：'”目标=_blank>Quo accusamus itaque esse aliquid error reprehenderit！'，}；我想在jquery中使用它。当我警告该变量时，我应该在alertvar Events={'10-17-2018'：''，'09-22-2018'：''，}中获取object对象；我想在jquery中这样做。当我提醒这个变量时，我应该在alertyou中获取[object object]，你说它是简单的php字符串，那么如何获取object呢？