Javascript变量范围问题

Javascript变量范围问题,javascript,function,variables,scope,Javascript,Function,Variables,Scope,我有一个变量mutedUser,我希望它能持久化到另一个函数。我在click事件外部持久化变量时遇到了一些问题。根据if语句的条件,“return mutedUser”保持“muted”字符串加法的最佳方式是什么?谢谢 *console.log让我检查持久性停止的位置 this.isUserMuted = function isUserMuted(payload) { var mutedUser = ''; // If mute button is clicked place them

我有一个变量mutedUser,我希望它能持久化到另一个函数。我在click事件外部持久化变量时遇到了一些问题。根据if语句的条件,“return mutedUser”保持“muted”字符串加法的最佳方式是什么?谢谢

*console.log让我检查持久性停止的位置

this.isUserMuted = function isUserMuted(payload) {
  var mutedUser = '';
  // If mute button is clicked place them into muted users list
  // check for duplicates in list
  $("#messages-wrapper").off('click', '.message button.muteButton');
  $("#messages-wrapper").on('click', '.message button.muteButton', function(e) {

      $('#unMute').show();

      //create userId reference variable
      var chatUserID = parseInt($(this).parent().parent().attr("data-type"));

      //store userId in muted user object
      mutedUsers[chatUserID] = {};
      mutedUsers[chatUserID].id = chatUserID;
      mutedUsers[chatUserID].muted = true;

      if (mutedUsers[chatUserID] !== null && mutedUsers[chatUserID].id === payload.a) {
          console.log("user is now muted");
          mutedUser += ' muted';
          console.log(mutedUser + 1);
      }
      console.log(mutedUser + 2);
  });
  return mutedUser;
};
编辑

对不起,我弄错了。另一种方法是传入该变量,即

this.isUserMuted = function isUserMuted(payload, isMuted) {
  isMuted = '';
  // If mute button is clicked place them into muted users list
  // check for duplicates in list
  $("#messages-wrapper").off('click', '.message button.muteButton');
  $("#messages-wrapper").on('click', '.message button.muteButton', function(e) {

      $('#unMute').show();

      //create userId reference variable
      var chatUserID = parseInt($(this).parent().parent().attr("data-type"));

      //store userId in muted user object
      mutedUsers[chatUserID] = {};
      mutedUsers[chatUserID].id = chatUserID;
      mutedUsers[chatUserID].muted = true;

      if (mutedUsers[chatUserID] !== null && mutedUsers[chatUserID].id === payload.a) {
          console.log("user is now muted");
          isMuted += ' muted';
          console.log(mutedUser + 1);
      }
      console.log(mutedUser + 2);
  });
  return isMuted;
};

如果我(通过查看代码)理解了您的意图,这将是最好的方法:

// If mute button is clicked place them into muted users list
// check for duplicates in list
$("#messages-wrapper").off('click', '.message button.muteButton');
$("#messages-wrapper").on('click', '.message button.muteButton', function(e) {
    $('#unMute').show();

    //create userId reference variable
    var chatUserID = parseInt($(this).parent().parent().attr("data-type"));

    //store userId in muted user object
    mutedUsers[chatUserID] = {};
    mutedUsers[chatUserID].id = chatUserID;
    mutedUsers[chatUserID].muted = true;
});

this.isUserMuted = function isUserMuted(payload) {
  var mutedUser = '';

  if (mutedUsers[payload.a] !== null) {
      mutedUser += ' muted';
  }

  return mutedUser;
};
代码保留
mutedUsers
数组,并且
isUserMuted
函数检查提供的用户是否在该数组中。在您提供的代码中,您将在每次调用
isusermute
函数时附加一个新的事件处理程序

isusermute
功能甚至可以缩短为:

this.isUserMuted = function isUserMuted(payload) {
  return mutedUsers[payload.a] !== null ? ' muted' : '';
};

你不能。如果您从函数返回字符串,它将始终按值传递,即复制;它的价值不会再改变了。您需要返回一个可以访问局部变量当前值的函数,或者返回一个属性正在更改的对象

由于您似乎已经有了一个对象,选项2将非常适合这里:

function User() { // or whatever you have
    …

    var user = this;
    // If mute button is clicked place them into muted users list
    // check for duplicates in list
    $("#messages-wrapper").on('click', '.message button.muteButton', function(e) {

        $('#unMute').show();

        //store userId in muted user object
        mutedUsers[user.id] = user;
        user.muted = true;
    });
    this.muted = false;
    this.isUserMuted = function() {
        return this.muted ? ' muted' : '';
    }
}

事实上,你原来的版本更好。新版本不行,你知道你是对的。但我通常将其视为一种模块模式,也就是说,类似这样的东西帮助我更好地理解了这个问题,这将非常有效,但是我需要在这个.isUserMuted函数的范围内使用变量“chatUserID”。这是因为,该变量基于一个单击事件,该事件检查在您的实现中加载的HTML中的一个属性,
chatUserID
实际上等于
payload.a
if用户确实被静音(根据您的if语句判断-
if(mutedUsers[chatUserID]!==null&&mutedUsers[chatUserID].id==payload.a)
这一行
mutedUsers[chatUserID].id=chatUserID;
在单击处理程序中)啊!一旦我将其设置为vs.!==谢谢你的帮助!没问题。我很高兴我能帮助你!检查NOTNULL和id的if语句是否有效?此外,您还可以这样做并发布结果:console.log(mutedUser+'muted1');