Javascript 在尝试隔离阵列的一部分时遇到困难：(

这是数组

[ 'michael@ecorp.com:qnyynf',
  'esteban@ecorp.com:uneyrl',
  'marquis@ecorp.com:gnlybe',
  'denver@ecorp.com:eboreg',
  'robin@ecorp.com:zbaxrl',
  'royce@ecorp.com:gubznf',
  'van@ecorp.com:fgnejnef',
  'tony@ecorp.com:cnff',
  'thomas@ecorp.com:zvpunry',
  'dave@ecorp.com:gvttre',
  'benjamin@ecorp.com:fhcrezna',
  'napoleon@ecorp.com:guhaqre',
  'luke@ecorp.com:enatre',
  'santos@ecorp.com:zvpuryyr',
  'orlando@ecorp.com:npprff',
  'wilbur@ecorp.com:cevaprff',
  'stan@ecorp.com:cnffjbeq',
  'kurtis@ecorp.com:fhafuvar',
  'dee@ecorp.com:fhzzre',
  'timothy@ecorp.com:wrffvpn' ]

我试图只移动每封用“：”索引的电子邮件的密码，但索引逗号会破坏它。 仍然是一个试图理解这些类型数组的noob

你将如何做到这一点

---

谢谢您的帮助！

您是否尝试过以下方法：

//define array (as you have)
const array = ["1a:1b", "2a:2b", "3a:3b", "4a:4b"];

//map each item within that array. 'item' in this context is any array item. So essentially below is similar to a 'for each' command.
const passwords_001 = array.map(item => {
    //I'm splitting each string, using the colon as the marker for 'seperator' 
    //i.e anything before or after it will be it's own item in the 'itemAsArray' array
    var itemAsArray = item.split(':');

    //pop() is taking the last item of the relevant array and removing it, but also returning it. 
    //This can then be passed as an item for the array we are mapping i.e passwords_001
    var password = itemAsArray.pop();

    //return the password as the new array item
    return password;
});

//log the passwords_001 array to see only the passwords returned
console.log(passwords_001);

//console output
//["1b", "2b", "3b", "4b"]

这个

console.log([ 'michael@ecorp.com：qnyynf'，'esteban@ecorp.com：uneyrl'，'marquis@ecorp.com：gnlybe'，'denver@ecorp.com：eboreg'，'robin@ecorp.com：zbaxrl'，'royce@ecorp.com：gubznf'，'van@ecorp.com：fgnejnef'，'tony@ecorp.com：cnff'，'thomas@ecorp.com：zvpunry'，'dave@ecorp.com：gvttre'，'benjamin@ecorp.com：fhcrezna'，'napoleon@ecorp.com：guhaqre'，'luke@ecorp.com：enatre'，'santos@ecorp.com：zvpuryyr'，'orlando@ecorp.com：npprff'，'wilbur@ecorp.com：cevaprff'，'stan@ecorp.com：cnffjbeq'，'kurtis@ecorp.com：fhafuvar'，'dee@ecorp.com：fhzzre'，'timothy@ecorp.com：wrffvpn']
.map（e=>e.split（“：”）[1]）；

您需要更加明确您的目标并更好地展示您的尝试预期的输出是什么？您可以展示一些您尝试过的代码吗？您是否也在尝试将密码移动到单独的数组中？不确定预期的输出是什么，但如果我理解正确，您需要：final=arr.map（el=>el.split）（“：”）[1]）；或者[0]，如果您只想要电子邮件……老实说，我已经尝试使用concat substring last index等转换为字符串。