Javascript 推特引导工具提示
我在服务器端动态创建了以下代码:Javascript 推特引导工具提示,javascript,php,jquery,twitter-bootstrap,twitter-bootstrap-tooltip,Javascript,Php,Jquery,Twitter Bootstrap,Twitter Bootstrap Tooltip,我在服务器端动态创建了以下代码: foreach($pages as $key => $value) { $link = path_get($value['tid'], $value['nid']) ; $pages[$key]['title'] = "<a href='".$link."' target='blank'>".$value['title'].($value['nid']==1?' (Accueil)':'')."</a>" ; $pages[$
foreach($pages as $key => $value)
{
$link = path_get($value['tid'], $value['nid']) ;
$pages[$key]['title'] = "<a href='".$link."' target='blank'>".$value['title'].($value['nid']==1?' (Accueil)':'')."</a>" ;
$pages[$key]['date_post'] = sql_to_datetime($value['date_post']) ;
$edit = "<a href='".url()."admin/page/edit/a/nid/".$value['nid']."' data-toggle='tooltip' title data-original-title='Default tooltip' >".IMG_EDIT."</a> " ;
$delete = "<a href='".url()."admin/page/index/a/action/delete/nid/".$value['nid']."' data-toggle='tooltip' title data-original-title='Default tooltip' class='delete-element'>".IMG_DELETE."</a> " ;
$pages[$key]['actions'] = $edit.(user_has_access_menu("page.delete")?$delete:'') ;
}
foreach($key=>$value的页面)
{
$link=path_get($value['tid'],$value['nid']);
$pages[$key]['title']='';
$pages[$key]['date\u post']=sql\u to\u datetime($value['date\u post']);
$edit=“”;
$delete=“”;
$pages[$key]['actions']=$edit(用户有权访问菜单(“page.delete”)?$delete:“”);
}
我想为每个编辑和删除按钮显示工具提示,但它不显示任何内容。请帮助
谢谢首先,您应该使用title=“blabla”,数据原始标题将由工具提示功能生成。功能…..在哪里?我可以看到你的变量。请更新你的完整代码,然后只有我们可以帮助你