Javascript 检查一个数组是否是另一个数组的子集(但检查属性)
我知道这是有效的(返回true) 但是,假设array1由对象组成,我想根据对象的某个属性检查array2:Javascript 检查一个数组是否是另一个数组的子集(但检查属性),javascript,jquery,arrays,function,object,Javascript,Jquery,Arrays,Function,Object,我知道这是有效的(返回true) 但是,假设array1由对象组成,我想根据对象的某个属性检查array2: var object1 = {name:'one'} var object2 = {name:'two'} var object3 = {name:'three'} var arr1 = [object1,object2,object3]; var arr2 = ['one','two']; var isSuperset = arr2.every(function (val) { re
var object1 = {name:'one'}
var object2 = {name:'two'}
var object3 = {name:'three'}
var arr1 = [object1,object2,object3];
var arr2 = ['one','two'];
var isSuperset = arr2.every(function (val) { return arr1.indexOf(val) >= 0; });
如何确保each函数检查name属性?
var arr3=arr1.map(函数(val){return val.name;})
并且在arr2.each的预测中,使用return arr3.indexOf(val)>=0代码>。哦,你更快了,同样的解决方案,向上投票
var object1 = {name: 'one'};
var object2 = {name: 'two'};
var object3 = {name: 'three'};
var arr1 = [object1,object2,object3];
var arr2 = ['one','two'];
// solution
var names = arr1.map(function(obj) {
return obj.name;
});
var isSuperset = arr2.every(function(val) {
return names.indexOf(val) >= 0;
});
alert(isSuperset);
var object1 = {name: 'one'};
var object2 = {name: 'two'};
var object3 = {name: 'three'};
var arr1 = [object1,object2,object3];
var arr2 = ['one','two'];
// solution
var names = arr1.map(function(obj) {
return obj.name;
});
var isSuperset = arr2.every(function(val) {
return names.indexOf(val) >= 0;
});
alert(isSuperset);