Javascript 通过动态接受数据输入来检索数据

我的Html文件

我的Php文件：

当我提交表单时，它显示如下错误

解析错误：解析错误，第8行的C:\wamp\www\New folder\data.php中应为T_字符串“orT_VARIABLE”或“T_NUM_字符串”

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实际上，我正在尝试检索名称halltickets如果我通过检查hallticket动态提交值，请告诉我问题出在哪里

“$\u GET[hallticket]”；我没听懂你能说清楚吗；mysqli_real_escape_string$con$hallpicket；从详细信息中选择*，其中hallticket='$hallticket'；试试“$”\u GET[hallticket]；但是你最好使用上面未定义的_变量给出的值。谢谢大家：谢谢帮助-干杯还有疑问，当我提交值时，它会在一个新页面中显示输出，我想用同样的方式在表单区域下显示它，你能帮我吗please@user3262425在这种情况下，您可能希望使用ajax或将表单提交给self并用html编写php代码。。。。。。Ajax总是一个更好的解决方案我很高兴@Undefined_变量

$hallticket = $_GET["hallticket"]; 
mysqli_real_escape_string($con,$hallticket); 
$result = mysqli_query($con,"SELECT * FROM details WHERE hallticket='$hallticket'"); 

<?php
$con=mysqli_connect("localhost","prabha","prabha","cvsr");
// Check connection
if (mysqli_connect_errno()) {
  echo "Failed to connect to MySQL: " . mysqli_connect_error();
}

$result = mysqli_query($con,"SELECT * FROM details WHERE hallticket='$_GET["hallticket"]'");

while($row = mysqli_fetch_array($result)) {
  echo $row['name'] . " " . $row['hallticket'];
  echo "<br>";
}
?>

$hallticket = $_GET["hallticket"]; 
mysqli_real_escape_string($con,$hallticket); 
$result = mysqli_query($con,"SELECT * FROM details WHERE hallticket='$hallticket'");