如何在javascript中执行递归方法

我试图创建一个递归方法来查找

但我不明白为什么它会找到元素，但返回未定义的

请问如何解决这个问题

这是我的密码：

export const findDmaFromHierarchy = (hierarchy: [], value: string): any => {
  let founded = undefined;
  hierarchy.forEach((dma: any) => {
    if (dma.children) {
      findDmaFromHierarchy(dma.children, value);
    }
    if (String(dma.value) === String(value)) {
      console.log("founded: ", dma);
      founded = Object.assign({}, dma);
      return founded;
    }
  });
  return founded;
};

当递归调用找到值时，不设置founded

export const findDmaFromHierarchy = (hierarchy: [], value: string): any => {
  let founded = undefined;
  hierarchy.forEach((dma: any) => {
    if (dma.children) {
      founded = findDmaFromHierarchy(dma.children, value);
      if (founded) {
        return founded;
      }
    }
    if (String(dma.value) === String(value)) {
      console.log("founded: ", dma);
      founded = Object.assign({}, dma);
      return founded;
    }
  });
  return founded;
};

你可以带上Arraysome，一找到就早点回来

然后，我建议检查是否找到了值，并分配对象，然后返回true。若要将此检查移动到函数前面，将忽略对子对象的不必要检查

对于孩子们，取一个临时变量并检查它，赋值并返回

export const findDmaFromHierarchy = (hierarchy: [], value: string): any => {
  let found = undefined;
  hierarchy.some((dma: any) => {
    if (String(dma.value) === String(value)) {
      console.log("founded: ", dma);
      found = Object.assign({}, dma);
      return true;
    }

    if (dma.children) {
      let temp = findDmaFromHierarchy(dma.children, value);
      if (temp) {
          found = temp;
          return tru;
      }
    }
  });
  return found;
};

---

您没有对递归调用的返回值执行任何操作。您无法从返回。forEach，请使用vanilla for Loop，因为您没有从'FindDdmaFromHierarchyDMA.children，value；'获取任何值保持不变