Javascript 带猫鼬的推入子阵

Javascript 带猫鼬的推入子阵,javascript,json,node.js,mongodb,mongoose,Javascript,Json,Node.js,Mongodb,Mongoose,我有一个三层深度的数据模型 var job = mongoose.Schema({ id:Number, jobName:String }); var demo = mongoose.Schema({ id:Number, demoName:String, job:[job] }); var ExerciseSchema = mongoose.Schema({

我有一个三层深度的数据模型

var job = mongoose.Schema({
        id:Number,
        jobName:String    
    });

var demo = mongoose.Schema({

            id:Number,
            demoName:String,
            job:[job]
    });

var ExerciseSchema = mongoose.Schema({

            id:Number,
            name:String,
            area:String,
            medicalObj:[demo]   
    });
var Exercise=mongoose.model('Exercise',ExerciseSchema)

我想在第二个嵌套数组中推送新对象

我正在尝试这种方法,但不起作用:

    Exercise.update({'area':area},{$push:{"medicalObj.job":{jobName:'Andrea'}}},{upsert:true},function(err){

        if(err){
                console.log("ERROR" + err);
        }else{
                console.log("Successfully");

        }
  });

我要注意的一点是:medicalObj将是一个对象数组。我认为您应该将jobName:andrea添加到包含在job中的特定数组中,所以这就是我在测试中所做的:

Exercise.findOne({area: area}, function(e,r){
  r.medicalObj.forEach(function(demo){
    // the following line looks for the specific array to add jobName Andrea to.
    if (demo.demoName == "test") {
      demo.job.push({jobName: "Andrea"});
      r.save(function(err, res){
        console.log(err, res);
      });
  });
});
如果您只希望插入jobName:“Andrea”,如果它不存在,您可以很容易地添加一个复选框,如下所示:

Exercise.findOne({area: area}, function(e,r){
  r.medicalObj.forEach(function(demo){
    if (demo.demoName == "test") {
      var found = false;
      demo.job.forEach(function(jobs){
        if (jobs.jobName == "Andrea") found == true;
      });
      if (found == false) {
        demo.job.push({jobName: "Andrea"});
        r.save(function(err, res){
          console.log(err, res);
        });
      };
    };
  });
});      

{'area':area}
{area:'area'}
?您有什么错误?相同的函数在数组的第二级工作。然而,我没有错误,只是不工作<代码>Exercise.update({'area':area},{$push:{medicalObj:{a:'Andrea'}}},{upsert:true},函数(err){if(err){console.log(“ERROR”+err);}else{console.log(“成功添加”);})