javascript-在ajax调用中显示加载程序&;得逞
我有点困惑 我正在用javascript创建一个表单,并将值发布到php页面(javascript-在ajax调用中显示加载程序&;得逞,javascript,ajax,Javascript,Ajax,我有点困惑 我正在用javascript创建一个表单,并将值发布到php页面(submit.php),如果php页面返回成功,我会将用户重定向到另一个页面success.php var url = 'submit.php'; var furl = 'success.php'; var formdata = new FormData(); formdata.append("name", 'John'); formdata.append('staffid',123); formdata.append
submit.php
),如果php页面返回成功,我会将用户重定向到另一个页面success.php
var url = 'submit.php';
var furl = 'success.php';
var formdata = new FormData();
formdata.append("name", 'John');
formdata.append('staffid',123);
formdata.append('csrf_test_name',csrf_token);
var ajax = new XMLHttpRequest();
ajax.addEventListener("load", function(event) {
uploadcomplete(event,furl);
}, false);
ajax.open("POST", url);
ajax.send(formdata);
function uploadcomplete(event,furl) {
var response = event.target.responseText.trim();
if(response=='Failed') {
alert('Failed');
} else {
alert('Success');
window.location.replace(furl);
}
}
function showLoader(){
document.getElementById('loader').style.display = 'block';
}
function hideLoader(){
document.getElementById('loader').style.display = 'none';
}
问题是,我想在表单数据获取过程中显示一个加载器图标,并在完成后隐藏它。为此,我创建了两个函数showLoader()
和hideLoader()
我的问题是,我应该在哪里包含这些函数?您可以这样做:
在请求进行过程中:
加载完成后:
您可以将其与事件一起使用:
var ajax = new XMLHttpRequest();
ajax.onreadystatechange = function(){
if(ajax.readyState === 0){
showLoader();
}else if(ajax.readyState === 4){
hideLoader();
}
};
或者在您的代码中,您可以在此处调用它们:
var ajax = new XMLHttpRequest();
ajax.addEventListener("load", function(event) {
uploadcomplete(event,furl);
hideLoader(); //<------------------hide the loader here when done.
}, false);
ajax.open("POST", url);
showLoader(); // <------------------call and show loader here.
ajax.send(formdata);
var ajax=new-XMLHttpRequest();
addEventListener(“加载”),函数(事件){
上传完成(事件,卷);
hideLoader();//对于纯JS,您可以这样做:
function loadData() {
var ajax = new XMLHttpRequest();
ajax.onreadystatechange = function() {
if (ajax.readyState === 4 ) {
if (ajax.status === 200) {
hideLoader();
//your code after ajax response, use ajax.responseText
}
else {
console.log('Some error...');
}
}
};
ajax.open("POST", url);
ajax.send(formdata);
showLoader();
}
因此,我应该包括ajax.addEventListener(“load”,function(event){uploadcomplete(event,furl);},false);在这两者之间,对吗?@Faouzi-oudouhin在ajax.open()之前包含它
var ajax = new XMLHttpRequest();
ajax.addEventListener("load", function(event) {
uploadcomplete(event,furl);
hideLoader(); //<------------------hide the loader here when done.
}, false);
ajax.open("POST", url);
showLoader(); // <------------------call and show loader here.
ajax.send(formdata);
function loadData() {
var ajax = new XMLHttpRequest();
ajax.onreadystatechange = function() {
if (ajax.readyState === 4 ) {
if (ajax.status === 200) {
hideLoader();
//your code after ajax response, use ajax.responseText
}
else {
console.log('Some error...');
}
}
};
ajax.open("POST", url);
ajax.send(formdata);
showLoader();
}