如何在Javascript中形成嵌套对象

我正在尝试使用JavaScript动态形成一个嵌套的树对象，如下所示，有人能告诉我实现这一点的最佳方法吗

 var contextpath= {
        text: "TreeRoot",
        items: [ {
            text: "subgroup1" ,
            items: [ {
                text: "subgroup2",
                items: [ {
                    text: "subgroup3",
                    items: [ {
                        text: "subgroup4",
                        items: [ {
                            text: "subgroup5"
                        }]
                    }]
                }]
            }]
        }]
    };

我已将试图转换为对象的分隔字符串（可以用作树组件的dat源）

var path=“TreeRoot | subgroup1 | subgroup2”

尝试实现如下内容，但使用较少数量的变量进行递归/循环

    var contextpathText= {};
    contextpathText.text ="TreeRoot";

    var childObject={};
    var items=[];
    childObject.text ="subgroup1";
    items.push(childObject);
    contextpathText.items=(items);

---

您需要一个深度计数器并存储正在处理的对象的当前级别

var obj = {text:''}, parent, child, i = 0;
obj.text = 'TreeRoot';
parent = obj;
while (++i <= 5) {
    if (parent.items === undefined) parent.items = []; // because you don't have an items on the last subgroup you can't put it in the object literal
    child = {text: 'subgroup'+i};
    parent.items.push(child);
    parent = child;
}
parent = child = null; // cleanup
obj;

---

编辑分隔字符串

var path = 'TreeRoot|subgroup1|subgroup2';

var obj = {text:''}, parent, child, levelText = path.split('|').reverse();
obj.text = levelText.pop() || '';
parent = obj;
while (levelText.length > 0) {
    child = {text: levelText.pop()};
    if (!parent.items) parent.items = [];
    parent.items.push(child);
    parent = child;
}
obj;

---

比我快，但我遵循以下准则：

var contextpath = { text: "TreeRoot", items: []}

var items = contextpath.items;

for(var i = 1; i <= 5; i++) {
    items.push({ text: "subgroup" + i, items: []});
    items = items[0].items;
}

---

看起来你做得不错。你到底想要实现什么？创建这个对象？参数是什么？你是否有一个数组要转换成这个数组，你只想创建一个像这样的

n

深对象，或者什么？subgroup2是subgroupofsubgroup1？是的，subgroup2是subgroupofsubgroup1。（即，subgro1是subgro2的父级）您需要多个字符串（坏主意）或多个分隔符（好主意）来定义何时深入树中，何时从该口袋中出来，何时返回其父级（或下一个子级）。非常欢迎您，但是Paul S.的回答更符合你的要求。

var contextpath = { text: "TreeRoot", items: []}

var items = contextpath.items;

for(var i = 1; i <= 5; i++) {
    items.push({ text: "subgroup" + i, items: []});
    items = items[0].items;
}

// snip
                text: "subgroup4",
                    items: [ {
                        text: "subgroup5",
                        items: []
                    }]
// etc.